This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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The mass of 9.5 moles of aluminum oxide (Al2O3) is 970 grams. Here's how to calculate it: 1. Determine the molar mass of Al2O3: Atomic mass of Aluminum (Al) = 26.98 g/mol Atomic mass of Oxygen (O) = 16.00 g/mol Molar mass of Al2O3 = (2 26.98 g/mol) + (3 * 16.00 g/mol) Molar mass of Al2O3 = 53.96 g/mol + 48.00 g/mol Molar mass of Al2O3 = 101.96 g/mol 2. Calculate the total mass: Mass = Number of moles Molar mass Mass = 9.5 moles 101.96 g/mol Mass = 968.62 g 3. Round to appropriate significant figures: Since 9.5 moles has two significant figures, the final answer should also be rounded to two significant figures. Mass = 970 g