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What is the separation technique T? Give the criterion to separate the mixtures. Separation technique T, Criterion: Deduce the names of liquids P and Q. P. Q.

Chemistry

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9 steps

Part a· 1 step

  1. Identify the meaning of the numbers in the nuclide notation.

    In the nuclide notation ZAX^{A}_{Z}\text{X}, ZZ represents the atomic number and AA represents the mass number.

    • The number 16 is the atomic number (ZZ), which represents the number of protons in the nucleus of element A. It also indicates the number of electrons in a neutral atom.
    • The number 32 is the mass number (AA), which represents the total number of protons and neutrons in the nucleus of element A.

Part b(i)· 2 steps

  1. Determine the number of valence electrons from the atomic number.

    Element A has an atomic number of 16. Its electron configuration is 2, 8, 6. It has 6 valence electrons.

  2. Identify the group in the Periodic Table.

    Elements with 6 valence electrons belong to Group 16 (or VIA) of the Periodic Table.
    The group of element A is Group 16.

Part b(ii)· 1 step

  1. Identify the element using its atomic number.

    An element with an atomic number of 16 is Sulfur.
    Element A is Sulfur (S).

Part c(i)· 2 steps

  1. Determine the valence electrons for Sulfur and Hydrogen.

    Sulfur (S) has 6 valence electrons. Hydrogen (H) has 1 valence electron.

  2. Draw the dot and cross diagram for the compound formed between Sulfur and Hydrogen.

    Sulfur needs 2 electrons to complete its octet, and each hydrogen needs 1 electron to complete its duet. Thus, one sulfur atom will bond with two hydrogen atoms to form H2S\text{H}_2\text{S} (hydrogen sulfide) through covalent bonding.

    H⋅S××⋅HorH−S⋅⋅⋅⋅−H\text{H} \cdot \underset{\times}{\overset{\times}{\text{S}}} \cdot \text{H} \quad \text{or} \quad \text{H} - \underset{\cdot \cdot}{\overset{\cdot \cdot}{\text{S}}} - \text{H}

    The dot and cross diagram for H2S\text{H}_2\text{S} is:

    H∙×S∙∙××∙H\text{H} \underset{\times}{\bullet} \underset{\times}{\overset{\bullet \bullet}{\text{S}}} \underset{\bullet}{\times} \text{H}

    (where ∙\bullet represents electrons from Sulfur and ×\times represents electrons from Hydrogen)

Part c(ii)· 3 steps

  1. Describe the bonding in the compound formed in (c)(i), which is H2S\text{H}_2\text{S}.

    The compound H2S\text{H}_2\text{S} is formed between two non-metals (Hydrogen and Sulfur). They share electrons to achieve stable electron configurations, forming covalent bonds.

  2. Describe the bonding in calcium oxide (CaO\text{CaO}).

    Calcium oxide (CaO\text{CaO}) is formed between a metal (Calcium, Group 2) and a non-metal (Oxygen, Group 16). Calcium loses 2 electrons to form Ca2+\text{Ca}^{2+} ions, and Oxygen gains 2 electrons to form O2−\text{O}^{2-} ions. The electrostatic attraction between these oppositely charged ions forms an ionic bond.

  3. Compare the two types of bonding.

    The compound formed between element A (Sulfur) and hydrogen (H2S\text{H}_2\text{S}) exhibits covalent bonding, where electrons are shared between atoms. In contrast, calcium oxide (CaO\text{CaO}) exhibits ionic bonding, where electrons are transferred from one atom to another, resulting in the formation of ions that are held together by strong electrostatic forces.

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