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Computer Science

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Step-by-step solution

26 steps

Here is the completed conversion table:

DecimalBinaryOctalHexadecimal
331000014121
117111010116575
4511110000117031C3
4311101011116571AF

Here are the step-by-step conversions for each row:

Row 1: Given Decimal 33

  • Decimal to Binary:
  1. Divide 33 by 2 repeatedly and record the remainders.

    $$
    33 \div 2 = 16 \text{ R } 1
    $$
    $$
    16 \div 2 = 8 \text{ R } 0
    $$
    $$
    8 \div 2 = 4 \text{ R } 0
    $$
    $$
    4 \div 2 = 2 \text{ R } 0
    $$
    $$
    2 \div 2 = 1 \text{ R } 0
    $$
    $$
    1 \div 2 = 0 \text{ R } 1
    $$
    
  2. Read the remainders from bottom to top.

    Binary: $\boxed{\text{100001}}$
    
    • Decimal to Octal:
  3. Divide 33 by 8 repeatedly and record the remainders.

    $$
    33 \div 8 = 4 \text{ R } 1
    $$
    $$
    4 \div 8 = 0 \text{ R } 4
    $$
    
  4. Read the remainders from bottom to top.

    Octal: $\boxed{\text{41}}$
    
    • Decimal to Hexadecimal:
  5. Divide 33 by 16 repeatedly and record the remainders.

    $$
    33 \div 16 = 2 \text{ R } 1
    $$
    $$
    2 \div 16 = 0 \text{ R } 2
    $$
    
  6. Read the remainders from bottom to top.

    Hexadecimal: $\boxed{\text{21}}$
    

    Row 2: Given Binary 1110101

    • Binary to Decimal:
  7. Assign powers of 2 to each binary digit from right to left, starting with 202^0.

    $$
    1 \cdot 2^6 + 1 \cdot 2^5 + 1 \cdot 2^4 + 0 \cdot 2^3 + 1 \cdot 2^2 + 0 \cdot 2^1 + 1 \cdot 2^0
    $$
    
  8. Calculate the sum.

    $$
    64 + 32 + 16 + 0 + 4 + 0 + 1 = 117
    $$
    Decimal: $\boxed{\text{117}}$
    
    • Binary to Octal:
  9. Group the binary digits into sets of three from right to left.

    Add leading zeros if necessary. 1 110 101 1 \ 110 \ 101

  10. Convert each group of three binary digits to its octal equivalent.

    $$
    001_2 = 1_8
    $$
    $$
    110_2 = 6_8
    $$
    $$
    101_2 = 5_8
    $$
    Octal: $\boxed{\text{165}}$
    
    • Binary to Hexadecimal:
  11. Group the binary digits into sets of four from right to left.

    Add leading zeros if necessary. 0111 0101 0111 \ 0101

  12. Convert each group of four binary digits to its hexadecimal equivalent.

    $$
    0111_2 = 7_{16}
    $$
    $$
    0101_2 = 5_{16}
    $$
    Hexadecimal: $\boxed{\text{75}}$
    

    Row 3: Given Octal 703

    • Octal to Decimal:
  13. Assign powers of 8 to each octal digit from right to left, starting with 808^0.

    $$
    7 \cdot 8^2 + 0 \cdot 8^1 + 3 \cdot 8^0
    $$
    
  14. Calculate the sum.

    $$
    7 \cdot 64 + 0 \cdot 8 + 3 \cdot 1 = 448 + 0 + 3 = 451
    $$
    Decimal: $\boxed{\text{451}}$
    
    • Octal to Binary:
  15. Convert each octal digit to its 3-bit binary equivalent.

    $$
    7_8 = 111_2
    $$
    $$
    0_8 = 000_2
    $$
    $$
    3_8 = 011_2
    $$
    
  16. Combine the binary groups.

    Binary: $\boxed{\text{111000011}}$
    
    • Octal to Hexadecimal:
  17. Convert Octal to Binary (as above).

    $$
    703_8 = 111000011_2
    $$
    
  18. Group the binary digits into sets of four from right to left.

    Add leading zeros if necessary. 0001 1100 0011 0001 \ 1100 \ 0011

  19. Convert each group of four binary digits to its hexadecimal equivalent.

    $$
    0001_2 = 1_{16}
    $$
    $$
    1100_2 = C_{16}
    $$
    $$
    0011_2 = 3_{16}
    $$
    Hexadecimal: $\boxed{\text{1C3}}$
    

    Row 4: Given Hexadecimal 1AF

    • Hexadecimal to Decimal:
  20. Assign powers of 16 to each hexadecimal digit from right to left, starting with 16016^0.

    (Note: A=10, F=15) 1⋅162+A⋅161+F⋅160 1 \cdot 16^2 + A \cdot 16^1 + F \cdot 16^0 1⋅162+10⋅161+15⋅160 1 \cdot 16^2 + 10 \cdot 16^1 + 15 \cdot 16^0

  21. Calculate the sum.

    $$
    1 \cdot 256 + 10 \cdot 16 + 15 \cdot 1 = 256 + 160 + 15 = 431
    $$
    Decimal: $\boxed{\text{431}}$
    
    • Hexadecimal to Binary:
  22. Convert each hexadecimal digit to its 4-bit binary equivalent.

    $$
    1_{16} = 0001_2
    $$
    $$
    A_{16} = 1010_2
    $$
    $$
    F_{16} = 1111_2
    $$
    
  23. Combine the binary groups.

    Leading zeros can be omitted.
    Binary: 110101111\boxed{\text{110101111}}

    • Hexadecimal to Octal:
  24. Convert Hexadecimal to Binary (as above).

    $$
    1AF_{16} = 000110101111_2
    $$
    
  25. Group the binary digits into sets of three from right to left.

    Add leading zeros if necessary. 000 110 101 111 000 \ 110 \ 101 \ 111

  26. Convert each group of three binary digits to its octal equivalent.

    $$
    000_2 = 0_8
    $$
    $$
    110_2 = 6_8
    $$
    $$
    101_2 = 5_8
    $$
    $$
    111_2 = 7_8
    $$
    Octal: $\boxed{\text{657}}$
    
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