This computer science problem involves algorithmic thinking and programming concepts. The solution below explains the approach, logic, and implementation step by step.

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Answer
C
Step 1: Check for Reflexivity. A relation on a set is reflexive if for every , . For the given relation, means that the word has at least one letter in common with itself. This is always true, as any word shares all its letters with itself. Therefore, is reflexive.
Step 2: Check for Symmetry. A relation on a set is symmetric if for every , if , then . If , it means that words and have at least one letter in common. If and have a common letter, then and also have that same letter in common. Therefore, is symmetric.
Step 3: Check for Transitivity. A relation on a set is transitive if for every , if and , then . Let's test this with an example: Let Let Let
Step 4: Conclude the properties of . The relation is reflexive, symmetric, and not transitive.
Step 5: Select the correct option. Based on the analysis, option (C) states "reflexive, symmetric, & not transitive", which matches our findings.
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Check for Reflexivity. A relation R on a set W is reflexive if for every x W, (x, x) R.
This computer science problem involves algorithmic thinking and programming concepts. The solution below explains the approach, logic, and implementation step by step.