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Determine the loaded voltage gain of the first stage using the provided formula and parameters.

Computer Science

ScanSolve AI Answer

Answer

C\text{C}

Step-by-step solution

4 steps

To determine the loaded voltage gain of the first stage, we need to consider the no-load voltage gain of that stage and the loading effect of the subsequent stage.

  1. Identify the relevant parameters for the first amplifier stage.

    The first CE amplifier stage has:

    • No-load voltage gain, AvNL1=−420A_{vNL1} = -420
    • Output impedance, Zo1=3.3 kΩZ_{o1} = 3.3 \text{ k}\Omega
  2. Determine the load connected to the output of the first stage.

    The output of the first stage is connected to the input of the second stage. Therefore, the load for the first stage is the input impedance of the second stage, Zi2Z_{i2}.
    From the diagram, Zi2=1 kΩZ_{i2} = 1 \text{ k}\Omega.

  3. Apply the formula for loaded voltage gain.

    The loaded voltage gain (AvA_v) of an amplifier stage is given by the formula:

    Av=AvNL⋅RL′Zo+RL′A_v = A_{vNL} \cdot \frac{R_L'}{Z_o + R_L'}

    where AvNLA_{vNL} is the no-load voltage gain, ZoZ_o is the output impedance of the stage, and RL′R_L' is the load connected to its output.

    For the first stage, substituting the values:

    Av1=AvNL1⋅Zi2Zo1+Zi2A_{v1} = A_{vNL1} \cdot \frac{Z_{i2}}{Z_{o1} + Z_{i2}} Av1=−420⋅Zi2Zo1+Zi2A_{v1} = -420 \cdot \frac{Z_{i2}}{Z_{o1} + Z_{i2}}
  4. Compare with the given options.

    Comparing our derived formula with the options, option C matches:
    C) −420⋅Zi2Zo1+Zi2-420 \cdot \frac{Z_{i2}}{Z_{o1} + Z_{i2}}

    The final answer is C\text{C}.

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