Explain the range of numbers in two's complement for n bits and demonstrate adding 63 and -64 using 7 bits in 2's complement.

April 12, 2026Computer Science

ScanSolve AI Answer

April 12, 2026

Answer

$-2^{n-1} to 2^{n-1} - 1$

Morning — let's get this done.

1.a.i) Range of numbers in two's complement for $n$ bits The range of numbers that can be represented in $n$ -bit two's complement is from $-2^{n-1}$ to $2^{n-1} - 1$ . $\boxed{-2^{n-1} to 2^{n-1} - 1}$

1.a.ii) Add 63 and -64 using 7 bits in 2's complement

Step 1: Convert 63 to 7-bit binary. $63_{10} = 0111111_2$

Step

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Morning — let's get this done. 1.a.i) Range of numbers in two's complement for n bits The range of numbers that can be represented in n-bit two's complement is from -2^n-1 to 2^n-1 - 1.

Asked on April 12, 2026Computer Science

This computer science problem involves algorithmic thinking and programming concepts. The solution below explains the approach, logic, and implementation step by step.

ScanSolve AI AnswerAnswered on April 12, 2026

Morning — let's get this done. 1.a.i) Range of numbers in two's complement for n bits The range of numbers that can be represented in n-bit two's complement is from -2^n-1 to 2^n-1 - 1. -2^n-1 to 2^n-1 - 1 1.a.ii) Add 63 and -64 using 7 bits in 2's complement Step 1: Convert 63 to 7-bit binary. 63_10 = 0111111_2 Step