The probability mass function (PMF) for the random variable Y is given by the table:

April 30, 2026Computer Science

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April 30, 2026

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y) = 1$$

Here's the solution to your probability problem.

The probability mass function (PMF) for the random variable $Y$ is given by the table: $Y$ : 0, 1, 2, 3, 4 $P(Y)$ : $\frac{1}{8}$ , $2k$ , $\frac{1}{6}$ , $3k$ , $\frac{2}{7}$

I) Find the value of $k$

Step 1: The sum of all probabilities in a PMF must equal 1. $\sum P(Y=y) = 1$ $\frac{1}{8} + 2k + \frac{1}{6} + 3k + \frac{2}{7} = 1$

Step 2: Combine like terms and fractions. $5k + \left(\frac{1}{8} + \frac{1}{6} + \frac{2}{7}\right) = 1$

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Asked on April 30, 2026Computer Science

This computer science problem involves algorithmic thinking and programming concepts. The solution below explains the approach, logic, and implementation step by step.

ScanSolve AI AnswerAnswered on April 30, 2026

Here's the solution to your probability problem. The probability mass function (PMF) for the random variable Y is given by the table: Y: 0, 1, 2, 3, 4 P(Y): (1)/(8), 2k, (1)/(6), 3k, (2)/(7) I) Find the value of k Step 1: The sum of all probabilities in a PMF must equal 1. P(Y=y) = 1 (1)/(8) + 2k + (1)/(6) + 3k + (2)/(7) = 1 Step 2: Combine like terms and fractions. 5k + ((1)/(8) + (1)/(6) + (2)/(7)) = 1