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The probability mass function (PMF) for the random variable Y is given by the table:

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The probability mass function (PMF) for the random variable YY is given by the table:
YY: 0, 1, 2, 3, 4
P(Y)P(Y): 18\frac{1}{8}, 2k2k, 16\frac{1}{6}, 3k3k, 27\frac{2}{7}

I) Find the value of kk

  1. The sum of all probabilities in a PMF must equal 1.

    ∑P(Y=y)=1\sum P(Y=y) = 1 18+2k+16+3k+27=1\frac{1}{8} + 2k + \frac{1}{6} + 3k + \frac{2}{7} = 1
  2. Combine like terms and fractions.

    5k+(18+16+27)=15k + \left(\frac{1}{8} + \frac{1}{6} + \frac{2}{7}\right) = 1
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