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Complete the table by calculating the values of the given expressions for each value of Y.

Mathematics

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The table requires calculating the values of the given expressions for each value of YY. I will assume the "5%" in the first row, second column is a typo and should be "5".

Here is the completed table:

Y2468101214163+Y579111315171912Y+123456789(3+Y)2254981121169225289361(12Y+1)249162536496481\begin{array}{|c|c|c|c|c|c|c|c|c|} \hline Y & 2 & 4 & 6 & 8 & 10 & 12 & 14 & 16 \\ \hline 3+Y & 5 & 7 & 9 & 11 & 13 & 15 & 17 & 19 \\ \hline \frac{1}{2}Y+1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 \\ \hline (3+Y)^2 & 25 & 49 & 81 & 121 & 169 & 225 & 289 & 361 \\ \hline \left(\frac{1}{2}Y+1\right)^2 & 4 & 9 & 16 & 25 & 36 & 49 & 64 & 81 \\ \hline \end{array}

To illustrate the calculations, let's use Y=2Y=2 as an example for each expression:

Step 1: Calculate for Y=2Y=2.

  • For 3+Y3+Y: Substitute Y=2Y=2 into the expression.
3+2=53+2 = \boxed{5}
  • For 12Y+1\frac{1}{2}Y+1: Substitute Y=2Y=2 into the expression.
12(2)+1=1+1=2\frac{1}{2}(2)+1 = 1+1 = \boxed{2}
  • For (3+Y)2(3+Y)^2: Substitute Y=2Y=2 into the expression.
(3+2)2=52=25(3+2)^2 = 5^2 = \boxed{25}
  • For (12Y+1)2\left(\frac{1}{2}Y+1\right)^2: Substitute Y=2Y=2 into the expression.
(12(2)+1)2=(1+1)2=22=4\left(\frac{1}{2}(2)+1\right)^2 = (1+1)^2 = 2^2 = \boxed{4}

The remaining values in the table are calculated similarly by substituting each YY value into the respective expression.

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