To complete the table, we calculate the values for 3x-2, x+1, and y = (3x−2)/(x+1) for each given x value.

Here's the completed table for question 8(a):

To complete the table, we calculate the values for $3x-2$, $x+1$, and $y = \frac{3x-2}{x+1}$ for each given $x$ value.

For $x = -1$:
$3x-2 = 3(-1)-2 = -3-2 = -5$
$x+1 = -1+1 = 0$
$y = \frac{-5}{0}$, which is undefined.

The completed table is as follows:

$$\begin{array}{|c|c|c|c|c|c|c|c|c|c|c|} \hline x & -4 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline 3x-2 & -14 & -11 & -8 & -5 & -2 & 1 & 4 & 7 & 10 & 13 \\ \hline x+1 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline y = \frac{3x-2}{x+1} & 4.67 & 5.5 & 8 & - & -2 & 0.5 & 1.33 & 1.75 & 2 & 2.17 \\ \hline \end{array}$$