Copy and complete the table of values for the relations y1 = 2x + 5 and y2 = 3 − 2x for x from -4 to 3.

We substitute each $x$ value into the function $y_1 = 2x + 5$.

For $x = -3$:

$$y_1 = 2(-3) + 5 = -6 + 5 = \boxed{\textbf{-1}}$$

For $x = -2$:

$$y_1 = 2(-2) + 5 = -4 + 5 = \boxed{\textbf{1}}$$

For $x = 0$:

$$y_1 = 2(0) + 5 = 0 + 5 = \boxed{\textbf{5}}$$

For $x = 2$:

$$y_1 = 2(2) + 5 = 4 + 5 = \boxed{\textbf{9}}$$

For $x = 3$:

$$y_1 = 2(3) + 5 = 6 + 5 = \boxed{\textbf{11}}$$

We substitute each $x$ value into the function $y_2 = 3 - 2x$.

For $x = -2$:

$$y_2 = 3 - 2(-2) = 3 + 4 = \boxed{\textbf{7}}$$

For $x = 0$:

$$y_2 = 3 - 2(0) = 3 - 0 = \boxed{\textbf{3}}$$

For $x = 1$:

$$y_2 = 3 - 2(1) = 3 - 2 = \boxed{\textbf{1}}$$

For $x = 2$:

$$y_2 = 3 - 2(2) = 3 - 4 = \boxed{\textbf{-1}}$$

For $x = 3$:

$$y_2 = 3 - 2(3) = 3 - 6 = \boxed{\textbf{-3}}$$

Note: The value for $y_2$ at $x=3$ in the original table is given as 11, which contradicts the relation $y_2 = 3 - 2x$. The calculated value is -3.

The completed table is:

X	-4	-3	-2	-1	0	1	2	3
$y_1 = 2x + 5$	-3	-1	1	3	5	7	9	11
$y_2 = 3 - 2x$	11	9	7	5	3	1	-1	-3