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Complete the table for the function y = (3x−2)/(x+1) for x values ranging from -4 to 5.

Mathematics

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Answer

To complete the table for y=3x−2x+1y = \frac{3x-2}{x+1}, we need to calculate the values of 3x−23x-2, x+1x+1, and yy for each given xx value. The table provided in the image is already complete with all the necessary values.

Graph of y = (3x − 2)/(x + 1)

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Key points of y = (3x − 2)/(x + 1)
Pointxy
y-intercept0−2
x-intercept0.670

Here is the completed table:

x−4−3−2−10123453x−2−14−11−8−5−21471013x+1−3−2−10123456y=3x−2x+14.675.58−−20.51.331.7522.17\begin{array}{|c|c|c|c|c|c|c|c|c|c|c|} \hline x & -4 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline 3x-2 & -14 & -11 & -8 & -5 & -2 & 1 & 4 & 7 & 10 & 13 \\ \hline x+1 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline y = \frac{3x-2}{x+1} & 4.67 & 5.5 & 8 & - & -2 & 0.5 & 1.33 & 1.75 & 2 & 2.17 \\ \hline \end{array}

Explanation of values:

  • For x=−1x = -1, x+1=0x+1 = 0, so y=−50y = \frac{-5}{0} is undefined, indicated by a dash.
  • All other values are calculated by substituting xx into the expressions 3x−23x-2, x+1x+1, and then dividing to find yy. For example, when x=2x=2, 3x−2=3(2)−2=43x-2 = 3(2)-2 = 4, x+1=2+1=3x+1 = 2+1 = 3, and y=43≈1.33y = \frac{4}{3} \approx 1.33.
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