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Create a table of values for the functions y = 4−x and y = 3x−8 for x values from -1 to 6.

Mathematics

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Step-by-step solution

4 steps
  1. Identify the range of xx values.

    The interval is −1≤x≤6-1 \le x \le 6. Since these are linear functions, we will use integer values for xx within this interval:

    x∈{−1,0,1,2,3,4,5,6}x \in \{-1, 0, 1, 2, 3, 4, 5, 6\}
  2. Calculate the values for the first function, y=4−xy = 4-x, for each xx in the interval.

    • For x=−1x=-1: y=4−(−1)=4+1=5y = 4 - (-1) = 4+1 = 5
    • For x=0x=0: y=4−0=4y = 4 - 0 = 4
    • For x=1x=1: y=4−1=3y = 4 - 1 = 3
    • For x=2x=2: y=4−2=2y = 4 - 2 = 2
    • For x=3x=3: y=4−3=1y = 4 - 3 = 1
    • For x=4x=4: y=4−4=0y = 4 - 4 = 0
    • For x=5x=5: y=4−5=−1y = 4 - 5 = -1
    • For x=6x=6: y=4−6=−2y = 4 - 6 = -2
  3. Calculate the values for the second function, y=3x−8y = 3x-8, for each xx in the interval.

    • For x=−1x=-1: y=3(−1)−8=−3−8=−11y = 3(-1) - 8 = -3 - 8 = -11
    • For x=0x=0: y=3(0)−8=0−8=−8y = 3(0) - 8 = 0 - 8 = -8
    • For x=1x=1: y=3(1)−8=3−8=−5y = 3(1) - 8 = 3 - 8 = -5
    • For x=2x=2: y=3(2)−8=6−8=−2y = 3(2) - 8 = 6 - 8 = -2
    • For x=3x=3: y=3(3)−8=9−8=1y = 3(3) - 8 = 9 - 8 = 1
    • For x=4x=4: y=3(4)−8=12−8=4y = 3(4) - 8 = 12 - 8 = 4
    • For x=5x=5: y=3(5)−8=15−8=7y = 3(5) - 8 = 15 - 8 = 7
    • For x=6x=6: y=3(6)−8=18−8=10y = 3(6) - 8 = 18 - 8 = 10
  4. Construct the table of values.

    The completed table is:

    xy=4−xy=3x−8−15−1104−813−522−23114045−176−210\boxed{ \begin{array}{|c|c|c|} \hline x & y = 4-x & y = 3x-8 \\ \hline -1 & 5 & -11 \\ \hline 0 & 4 & -8 \\ \hline 1 & 3 & -5 \\ \hline 2 & 2 & -2 \\ \hline 3 & 1 & 1 \\ \hline 4 & 0 & 4 \\ \hline 5 & -1 & 7 \\ \hline 6 & -2 & 10 \\ \hline \end{array} }
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