What is the result of the following in sign-absolute notation? 01110100 - 01001100.

What is result of the following in sign-absolute notation? $01\ 110\ 100 - 01\ 001\ 100$.

• The first bit is the sign bit (0 for positive, 1 for negative). The remaining 6 bits represent the magnitude.
• First number: $01\ 110\ 100$
  • Sign: 0 (positive)
  • Magnitude: $110\ 100_2 = 1 \cdot 2^5 + 1 \cdot 2^4 + 0 \cdot 2^3 + 1 \cdot 2^2 + 0 \cdot 2^1 + 0 \cdot 2^0 = 32 + 16 + 4 = 52_{10}$
  • So, the first number is $+52$.
• Second number: $01\ 001\ 100$
  • Sign: 0 (positive)
  • Magnitude: $001\ 100_2 = 0 \cdot 2^5 + 0 \cdot 2^4 + 1 \cdot 2^3 + 1 \cdot 2^2 + 0 \cdot 2^1 + 0 \cdot 2^0 = 8 + 4 = 12_{10}$
  • So, the second number is $+12$.
• The operation is $52 - 12 = 40$.
• Now, convert $40_{10}$ to 6-bit binary magnitude: $40_{10} = 32 + 8 = 101000_2$.
• Since the result is positive, the sign bit is 0.
• Combining the sign bit and the 6-bit magnitude: $01\ 010\ 000$.

Let's re-evaluate the second number's magnitude from the image. It looks like $01\ 001\ 100$.
Magnitude: $001\ 100_2 = 0 \cdot 2^5 + 0 \cdot 2^4 + 1 \cdot 2^3 + 1 \cdot 2^2 + 0 \cdot 2^1 + 0 \cdot 2^0 = 8 + 4 = 12_{10}$.
So, $52 - 12 = 40$.
The binary representation of $40_{10}$ is $101000_2$.
In sign-magnitude notation (1 sign bit, 6 magnitude bits), this would be $01\ 010\ 000$.

Let's re-read the image carefully for the second number. It is $01\ 001\ 100$.
Magnitude: $001\ 100_2 = 12_{10}$.
So, $52 - 12 = 40$.
The result in sign-magnitude is $01\ 010\ 000$.

Checking the options:
A. $00\ 101\ 000$ (Magnitude $101000_2 = 40_{10}$)
B. $10\ 101\ 000$ (Negative $40_{10}$)
C. $00\ 010\ 000$ (Magnitude $010000_2 = 16_{10}$)
D. $10\ 011\ 000$ (Negative $011000_2 = 24_{10}$)

The calculated result $01\ 010\ 000$ matches option A.

• A. $00\ 101\ 000$

An Example of universal gate

• A universal gate is a logic gate that can implement any Boolean function without the need to use any other gate type. NAND and NOR gates are universal gates.
• C. NOR

It looks for an instruction, uses circuits to interpret it, and then carries out the instruction in a process known as the...

• This process describes the fundamental cycle of a CPU, which involves fetching an instruction, decoding it, and then executing it. This is known as the Machine Instruction Cycle.
• B. Machine Instruction Cycle

When the processor receives a signal, it stops what it is doing in order to attend to the request. The mechanism exploited here is:

• This mechanism is called interrupt handling. An interrupt signal causes the processor to pause its current task and execute a specific routine (interrupt service routine) to handle the request.
• C. Interrupt handling