25 + 1.25 kyu kiye English me samjhao

This is the point where the collision occurs.

It falls downwards. We calculated that it falls a distance of $1.25 \text{ m}$ in $0.5 \text{ s}$ (the time it takes for the first projectile to reach its maximum height).

To find the initial height from which the second projectile was dropped, we need to add:

• The height from the ground where the collision takes place ($1.25 \text{ m}$).
• The distance the second projectile fell before the collision ($1.25 \text{ m}$).

So, the initial height of the second projectile is:

This means the second projectile started at $2.5 \text{ m}$ above the ground, fell $1.25 \text{ m}$, and then collided with the first projectile at $1.25 \text{ m}$ above the ground.