Can u please process it in English

Okay, here is the solution in English.

a) Which metal can be displaced from its salt solution by all other metals in the table? Give a reason.

• Step 1: Compare the standard electrode potentials for all metals. The metal with the most negative electrode potential is the most reactive, and the metal with the most positive electrode potential is the least reactive.

  • G: $-0.76\,V$ (most reactive)
  • D: $-0.13\,V$
  • F: $+0.34\,V$
  • E: $+0.85\,V$ (least reactive)

• Step 2: A metal can be displaced from its salt solution by another metal if the other metal is more reactive. For a metal to be displaced by all other metals, it must be the least reactive metal.

  • Metal E has the most positive electrode potential ($+0.85\,V$), meaning it is the least reactive metal. Therefore, metals D, F, and G (which are all more reactive than E) can displace E from its salt solution.

• Answer: Metal E.

• Reason: Metal E has the highest (most positive) standard electrode potential, meaning it is the least reactive metal. Therefore, all other metals (D, F, G) which have lower (more negative) electrode potentials can displace it from its salt solution.

b) Metals F and G were connected to form a cell as shown in the diagram below.

i) Write the equation for the reactions occurring at the electrodes.

• Step 1: Identify which electrode is the anode and which is the cathode. The metal with the more negative electrode potential will be the anode (oxidation occurs), and the metal with the more positive electrode potential will be the cathode (reduction occurs).

  • G: $-0.76\,V$ (more negative, so it is the anode)
  • F: $+0.34\,V$ (more positive, so it is the cathode)

• Step 2: Write the oxidation half-reaction at the anode (G).

  • At the anode (G), metal G loses electrons to form $G^{2+}$ ions.
  $$G(s) \to G^{2+}(aq) + 2e^-$$

• Step 3: Write the reduction half-reaction at the cathode (F).

  • At the cathode (F), $F^{2+}$ ions from the solution gain electrons to form metal F.
  $$F^{2+}(aq) + 2e^- \to F(s)$$

ii) On the diagram, indicate with an arrow the direction in which electrons will flow.

• Answer: Electrons flow from the anode (where oxidation occurs) to the cathode (where reduction occurs) through the external circuit. Therefore, electrons will flow from Metal G to Metal F. (An arrow should be drawn on the external wire, pointing from G towards F).

iii) What is the function of the salt bridge?

• Answer: The function of the salt bridge is to complete the electrical circuit by allowing the flow of ions between the two half-cells. This helps to maintain charge neutrality in each half-cell, preventing charge build-up and ensuring a continuous flow of electrons.