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6) Given that y=2x2−3x+1y = 2x^2 - 3x + 1. Find the value of yy when x=−2x = -2.

  1. Substitute x=−2x = -2 into the given equation.

    y=2(−2)2−3(−2)+1y = 2(-2)^2 - 3(-2) + 1
  2. Perform the calculations following the order of operations (PEMDAS/BODMAS).

    y=2(4)−(−6)+1y = 2(4) - (-6) + 1 y=8+6+1y = 8 + 6 + 1 y=15y = 15

    The value of yy when x=−2x = -2 is 15\boxed{15}.

    7) Solve the equation 3(x−2)=123(x - 2) = 12.

  3. Distribute the 3 on the left side of the equation.

    3x−6=123x - 6 = 12
  4. Add 6 to both sides of the equation to isolate the term with xx.

    3x=12+63x = 12 + 6 3x=183x = 18
  5. Divide both sides by 3 to solve for xx.

    x=183x = \frac{18}{3} x=6x = 6

    The solution to the equation is x=6\boxed{x = 6}.

    8) A bag contains 5 red balls, 3 blue balls, and 2 green balls. A ball is picked at random from the bag. Find the probability that the ball picked is:

    a) Red

    b) Not green

  6. Calculate the total number of balls in the bag.

    Total number of balls = 5(red)+3(blue)+2(green)=105 (\text{red}) + 3 (\text{blue}) + 2 (\text{green}) = 10 balls.

    a) Red

  7. Determine the number of red balls.

    Number of red balls = 5.

  8. Calculate the probability of picking a red ball.

    P(Red)=Number of red ballsTotal number of ballsP(\text{Red}) = \frac{\text{Number of red balls}}{\text{Total number of balls}} P(Red)=510=12P(\text{Red}) = \frac{5}{10} = \frac{1}{2}

    The probability of picking a red ball is 12\boxed{\frac{1}{2}}.

    b) Not green

  9. Determine the number of balls that are not green.

    Number of not green balls = Total number of balls - Number of green balls = 10−2=810 - 2 = 8.

  10. Calculate the probability of picking a ball that is not green.

    P(Not green)=Number of not green ballsTotal number of ballsP(\text{Not green}) = \frac{\text{Number of not green balls}}{\text{Total number of balls}} P(Not green)=810=45P(\text{Not green}) = \frac{8}{10} = \frac{4}{5}

    The probability of picking a ball that is not green is 45\boxed{\frac{4}{5}}.

    9) Simplify x2−4x+2\frac{x^2 - 4}{x + 2}.

  11. Factor the numerator using the difference of squares formula, a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b).

    Here, x2−4=x2−22=(x−2)(x+2)x^2 - 4 = x^2 - 2^2 = (x - 2)(x + 2).

  12. Substitute the factored form into the expression.

    (x−2)(x+2)x+2\frac{(x - 2)(x + 2)}{x + 2}
  13. Cancel out the common factor (x+2)(x + 2) from the numerator and the denominator (assuming x≠−2x \neq -2).

    x−2x - 2

    The simplified expression is x−2\boxed{x - 2}.

    10) Find the equation of a straight line passing through the points (1,2)(1, 2) and (3,8)(3, 8).

  14. Calculate the slope (mm) of the line using the formula m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}.

    Let (x1,y1)=(1,2)(x_1, y_1) = (1, 2) and (x2,y2)=(3,8)(x_2, y_2) = (3, 8).

    m=8−23−1m = \frac{8 - 2}{3 - 1} m=62m = \frac{6}{2} m=3m = 3
  15. Use the point-slope form of a linear equation, y−y1=m(x−x1)y - y_1 = m(x - x_1).

    Using the point (1,2)(1, 2) and the calculated slope m=3m = 3:

    y−2=3(x−1)y - 2 = 3(x - 1)
  16. Convert the equation to the slope-intercept form, y=mx+cy = mx + c, by simplifying.

    y−2=3x−3y - 2 = 3x - 3 y=3x−3+2y = 3x - 3 + 2 y=3x−1y = 3x - 1

    The equation of the straight line is y=3x−1\boxed{y = 3x - 1}.

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