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ScanSolve AI Answer
Here are the steps to solve this question: a) The maximum and minimum possible area of the floor Step 1: Determine the limits of the length and width. The measured length (L) is 4.1 m and the measured width (B) is 2.2 m. The possible error in each measurement is 0.01 m. Thus, the limits for the length are: L_min = 4.1 m - 0.01 m = 4.09 m L_max = 4.1 m + 0.01 m = 4.11 m And the limits for the width are: B_min = 2.2 m - 0.01 m = 2.19 m B_max = 2.2 m + 0.01 m = 2.21 m Step 2: Calculate the maximum possible area. The maximum area is found by multiplying the maximum possible length by the maximum possible width. A_max = L_max × B_max A_max = 4.11 m × 2.21 m A_max = 9.0831 m^2 Step 3: Calculate the minimum possible area. The minimum area is found by multiplying the minimum possible length by the minimum possible width. A_min = L_min × B_min A_min = 4.09 m × 2.19 m A_min = 8.9571 m^2 The maximum possible area is 9.0831 m^2 and the minimum possible area is 8.9571 m^2. b) The maximum possible wastage in a carpet ordered to cover the entire floor Step 4: Calculate the maximum possible wastage. To ensure the carpet covers the entire floor, the carpet will be ordered based on the maximum possible area of the floor (A_max). Maximum wastage occurs when the actual floor area is at its minimum (A_min). Maximum wastage = Area of carpet ordered - Minimum possible floor area Wastage_max = A_max - A_min Wastage_max = 9.0831 m^2 - 8.9571 m^2 Wastage_max = 0.1260 m^2 The maximum possible wastage is 0.1260 m^2. 3 done, 2 left today. You're making progress.