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6. (i) Study the pseudocode below and answer the questions that follow.
a) The data type of the variable check is a string, as it is assigned the literal values "Yes" and "No".
b) Here is a trace of the algorithm for number = 10:
| i | num (initial) | check (initial) | Condition num * num <= i | i mod num = 0 | check (final) | num (final) | Output (print(i)) |
| :-- | :-------------- | :---------------- | :------------------------- | :-------------- | :-------------- | :-------------- | :------------------ |
| 2 | 2 | "Yes" | (False) | N/A | "Yes" | 2 | 2 |
| 3 | 2 | "Yes" | (False) | N/A | "Yes" | 2 | 3 |
| 4 | 2 | "Yes" | (True) | (True) | "No" | 3 | |
| | | | (False) | | | | |
| 5 | 2 | "Yes" | (True) | (False) | "Yes" | 3 | 5 |
| | | | (False) | | | | |
| 6 | 2 | "Yes" | (True) | (True) | "No" | 3 | |
| | | | (False) | | | | |
| 7 | 2 | "Yes" | (True) | (False) | "Yes" | 3 | 7 |
| | | | (False) | | | | |
| 8 | 2 | "Yes" | (True) | (True) | "No" | 3 | |
| | | | (False) | | | | |
| 9 | 2 | "Yes" | (True) | (False) | "Yes" | 3 | |
| | | | (True) | (True) | "No" | 4 | |
| | | | (False) | | | | |
| 10 | 2 | "Yes" | (True) | (True) | "No" | 3 | |
| | | | (True) | (False) | "No" | 4 | |
| | | | (False) | | | | |
The numbers printed are: .
c) The algorithm computes and displays the prime numbers up to the input number.
d) Here is a flowchart for the while loop:
graph TD
A[Initialize num = 2, check = "Yes"] --> B{num * num <= i ?};
B -- True --> C{i mod num = 0 ?};
C -- True --> D[check = "No"];
C -- False --> E[num = num + 1];
D --> E;
E --> B;
B -- False --> F[End while loop];
6. (ii) Iteration and recursion are different ways to execute a set of instructions repeatedly.
a)
• Iteration achieves repetition by using explicit loop constructs (e.g., for, while, repeat-until). A block of code is executed repeatedly as long as a condition is true or for a predefined number of times, with loop control variables being updated in each pass.
• Recursion achieves repetition when a function calls itself, either directly or indirectly. Each call creates a new instance of the function with its own local variables, and the repetition continues until a base condition (base case) is met, which terminates the sequence of calls.
b)
• Iteration does not terminate if the loop condition never becomes false (e.g., an infinite while loop) or if the loop counter does not converge to its termination value.
• Recursion does not terminate if no base case is defined, or if the base case is never reached. This leads to an excessive number of function calls and eventually a stack overflow.
c) Iteration is generally faster than recursion for several reasons: • Recursion involves significant overhead due to function calls (creating new stack frames, managing local variables, passing parameters, and returning values). These operations consume CPU time and memory. • Iteration, on the other hand, typically executes within a single stack frame and involves simpler jump instructions and variable updates, which reduces overhead. • While some compilers can optimize tail recursion into iteration, this is not always the case, and explicit iteration often remains more efficient in terms of performance.
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6. (i) Study the pseudocode below and answer the questions that follow.
This English question involves literary analysis, grammar, or writing skills. The detailed response below provides a well-structured answer with supporting evidence and clear explanations.