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Okay, Me❄️! Let's solve this redox equation in English, showing all the steps. To balance the redox equation Zn + BrO_3^- → Zn^2+ + Br^-, we will use the half-reaction method in an acidic medium. Step 1: Separate the equation into half-reactions for oxidation and reduction. Oxidation: Zn → Zn^2+ Reduction: BrO_3^- → Br^- Step 2: Balance atoms other than oxygen and hydrogen. The zinc (Zn) and bromine (Br) atoms are already balanced in each half-reaction. Step 3: Balance oxygen (O) atoms by adding water molecules (H_2O). Oxidation: Zn → Zn^2+ (no oxygen atoms) Reduction: BrO_3^- → Br^- + 3H_2O (3 oxygen atoms on the left, so add 3 H_2O on the right) Step 4: Balance hydrogen (H) atoms by adding hydrogen ions (H^+). Oxidation: Zn → Zn^2+ (no hydrogen atoms) Reduction: 6H^+ + BrO_3^- → Br^- + 3H_2O (6 hydrogen atoms on the right in 3 H_2O, so add 6 H^+ on the left) Step 5: Balance the charges by adding electrons (e^-). Oxidation: Left side charge: 0 Right side charge: +2 To balance, add 2 electrons to the right: Zn → Zn^2+ + 2e^- Reduction: Left side charge: (+6) + (-1) = +5 Right side charge: (-1) + (0) = -1 To balance, add 6 electrons to the left: 6e^- + 6H^+ + BrO_3^- → Br^- + 3H_2O Step 6: Multiply the half-reactions to equalize the number of electrons. The oxidation half-reaction has 2 electrons, and the reduction half-reaction has 6 electrons. Multiply the oxidation half-reaction by 3: 3 × (Zn → Zn^2+ + 2e^-) 3Zn → 3Zn^2+ + 6e^- The reduction half-reaction remains unchanged: 6e^- + 6H^+ + BrO_3^- → Br^- + 3H_2O Step 7: Add the half-reactions and cancel common terms. 3Zn + (6e^- + 6H^+ + BrO_3^-) → (3Zn^2+ + 6e^-) + (Br^- + 3H_2O) Cancel the 6 electrons from both sides to get the balanced equation: 3Zn + 6H^+ + BrO_3^- → 3Zn^2+ + Br^- + 3H_2O Step 8: Verify the balance of atoms and charges. Atoms: Zn: 3 on left, 3 on right (balanced) Br: 1 on left, 1 on right (balanced) O: 3 on left, 3 on right (balanced) H: 6 on left, 6 on right (balanced) Charges: Left side: 0 + (+6) + (-1) = +5 Right side: 3 × (+2) + (-1) + 0 = +6 - 1 = +5 The charges are balanced. The balanced redox equation is: 3Zn + 6H^+ + BrO_3^- → 3Zn^2+ + Br^- + 3H_2O That's 2 down. 3 left today — send the next one.