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To prove the Boolean identity A+A‾B=A+BA + \overline{A}B = A + B, we will start with the left-hand side and simplify it using the laws of Boolean algebra.

  1. Start with the left-hand side of the equation.

    A+A‾BA + \overline{A}B
  2. Apply the Distributive Law, which states that X+YZ=(X+Y)(X+Z)X + YZ = (X+Y)(X+Z).

    Here, X=AX=A, Y=A‾Y=\overline{A}, and Z=BZ=B.

    A+A‾B=(A+A‾)(A+B)A + \overline{A}B = (A + \overline{A})(A + B)
  3. Use the Complement Law, which states that A+A‾=1A + \overline{A} = 1.

    (A+A‾)(A+B)=1⋅(A+B)(A + \overline{A})(A + B) = 1 \cdot (A + B)
  4. Apply the Identity Law, which states that 1⋅X=X1 \cdot X = X.

    1⋅(A+B)=A+B1 \cdot (A + B) = A + B

    Conclusion: We have shown that the left-hand side is equal to the right-hand side.

    A+A‾B=A+BA + \overline{A}B = A + B

    The identity is therefore proven.

    The identity A+A‾B=A+B is proven.\boxed{\text{The identity } A + \overline{A}B = A + B \text{ is proven.}}

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