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vi

112500 g112500 \text{ g}

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Here are the answers translated into English:

Part i

Name

  • (I) Gas P: Carbon monoxide (COCO)
  • (II) Liquid R: Sulphuric acid (H2SO4H_2SO_4)
  • (III) Residue S: Insoluble impurities

Part ii

The role of coke in this process is as a reducing agent. It removes oxygen from zinc oxide (ZnOZnO) and converts it into zinc (ZnZn).

Part iii

The main impurity removed in the separation chamber is iron or *lead

Part iv

Write the equation for the reaction that occurs in the

  • (I) Roaster: 2ZnS(s)+3O2(g)→2ZnO(s)+2SO2(g)2ZnS_{(s)} + 3O_{2(g)} \rightarrow 2ZnO_{(s)} + 2SO_{2(g)}
  • (II) Reaction Chamber II: ZnO(s)+C(s)→Zn(g)+CO(g)ZnO_{(s)} + C_{(s)} \rightarrow Zn_{(g)} + CO_{(g)}

Part v

Write the equation for the reaction that occurs between zinc metal and liquid R

Zn(s)+H2SO4(aq)→ZnSO4(aq)+H2(g)Zn_{(s)} + H_2SO_{4(aq)} \rightarrow ZnSO_{4(aq)} + H_{2(g)}

Part vi

112500 g112500 \text{ g}

Calculate the mass of zinc sulphide

  1. Find the mass of zinc sulphide in the ore.

    Mass of zinc sulphide=45%×250 kg\text{Mass of zinc sulphide} = 45\% \times 250 \text{ kg} Mass of zinc sulphide=0.45×250 kg=112.5 kg\text{Mass of zinc sulphide} = 0.45 \times 250 \text{ kg} = 112.5 \text{ kg}

  2. Convert the mass to grams.

    Mass of zinc sulphide=112.5 kg×1000 g/kg=112500 g\text{Mass of zinc sulphide} = 112.5 \text{ kg} \times 1000 \text{ g/kg} = \boxed{112500 \text{ g}}

Part vii

One commercial use of zinc metal is

  • To make alloys such as brass.
  • For galvanizing (coating iron with zinc to prevent rust).
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