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On the provided topographic map, draw a cross-section of the land along the line AB, indicating key elevation points and contour lines.

Geography

ScanSolve AI Answer

Answer

12

1:2.5\text{1:2.5}

Step-by-step solution

4 steps

Step 1: Understand the task for Question 11.

Part 11· 1 step

asks to draw a cross-section of the line AB from the topographic map. A cross-section shows the profile of the land along a specific line.

To draw a cross-section of line AB:

  1. Place a strip of paper along line AB on the map.
  2. Mark points A and B on the paper strip.
  3. Mark every point where a contour line intersects line AB on the paper strip.
  4. Label each marked point with its corresponding elevation (e.g., 100m, 150m, 200m, 250m, 300m). Point A is at 100m. The line crosses 150m, 200m, 250m, and 300m contours. The peak is inside the 300m contour, so its elevation is above 300m (e.g., 325m, assuming a 50m contour interval and the peak being roughly halfway to the next contour).
  5. Draw a horizontal line (x-axis) on a graph paper, representing the length of line AB.
  6. Draw a vertical line (y-axis) on the left, representing elevation, with a suitable scale (e.g., from 0m to 350m, with increments of 50m).
  7. Transfer the marked points from the paper strip to the x-axis of the graph.
  8. For each point, plot its corresponding elevation on the graph.
  9. Connect the plotted points with a smooth line to create the profile of the land along AB.

The resulting cross-section would show an upward slope from point A (100m), steadily increasing in elevation as it crosses the 150m, 200m, 250m, and 300m contour lines, reaching a peak (above 300m), and then descending slightly towards the end of the line segment B (if B is after the peak).

  1. Identify the given information for Question 12*.

Part 12

1:2.5\text{1:2.5}

asks to calculate the gradient of the slope from point C to point D.

The formula for gradient is given as:

Gradient=Vertical IntervalHorizontal distance\text{Gradient} = \frac{\text{Vertical Interval}}{\text{Horizontal distance}}
  1. Determine the Vertical Interval (VI)*.

    Point C is on the 100m contour line.
    Point D is on the 200m contour line.
    The vertical interval is the difference in elevation between point D and point C.

    Vertical Interval (VI)=Elevation of D−Elevation of C\text{Vertical Interval (VI)} = \text{Elevation of D} - \text{Elevation of C} VI=200 m−100 m\text{VI} = 200 \text{ m} - 100 \text{ m} VI=100 m\text{VI} = 100 \text{ m}
  2. Determine the Horizontal Distance (HD)*.

    The map includes a scale bar indicating 500m.
    By visual estimation from the image, the length of the line segment CD is approximately half the length of the 500m scale bar.
    Therefore, the horizontal distance between C and D is estimated to be:

    Horizontal Distance (HD)≈12×500 m\text{Horizontal Distance (HD)} \approx \frac{1}{2} \times 500 \text{ m} HD≈250 m\text{HD} \approx 250 \text{ m}
  3. Calculate the Gradient*.

    Now, substitute the values of the Vertical Interval and Horizontal Distance into the gradient formula.

    Gradient=VIHD\text{Gradient} = \frac{\text{VI}}{\text{HD}} Gradient=100 m250 m\text{Gradient} = \frac{100 \text{ m}}{250 \text{ m}} Gradient=1025\text{Gradient} = \frac{10}{25} Gradient=25\text{Gradient} = \frac{2}{5}

    The gradient can be expressed as a ratio.

    Gradient=1:2.5\text{Gradient} = 1 : 2.5

    The gradient of the slope from point C to point D is 1:2.5\boxed{\text{1:2.5}}.

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