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Study the table below and use the data presented to answer the questions that follow: a) What is the total Annual Rainfall (TAR) ? b) What is the annual Temperature Range(ATR) ? c) What is the Mean Annual Temperature(MAT) ?

Geography

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Answers

3 parts
a

i) 2138 mm\text{i) } \textbf{2138 mm}

b

ii) 1.4∘C\text{ii) } \textbf{1.4}^\circ\textbf{C}

c

iii) 27.18∘C\text{iii) } \textbf{27.18}^\circ\textbf{C}

Step-by-step solution

7 steps

Here are the calculations based on the provided table:

Part a· 2 steps

What is the total Annual Rainfall (TAR)?

  1. Sum all the monthly rainfall values from the table.

    TAR=399+221+157+139+112+95+100+187+167+206+120+235\text{TAR} = 399 + 221 + 157 + 139 + 112 + 95 + 100 + 187 + 167 + 206 + 120 + 235

  2. Perform the summation.

    TAR=2138 mm\text{TAR} = 2138 \text{ mm}

    The correct option is i).
    The total Annual Rainfall (TAR) is i) 2138 mm\boxed{\text{i) } \textbf{2138 mm}}.

Part b

ii) 1.4∘C\text{ii) } \textbf{1.4}^\circ\textbf{C}

What is the annual Temperature Range (ATR)?

  1. Identify the maximum and minimum monthly temperatures from the table.

    Maximum Temperature = 27.8∘C27.8^\circ\text{C} (May)
    Minimum Temperature = 26.4∘C26.4^\circ\text{C} (January)

  2. Calculate the difference between the maximum and minimum temperatures.

    ATR=Maximum Temperature−Minimum Temperature\text{ATR} = \text{Maximum Temperature} - \text{Minimum Temperature} ATR=27.8∘C−26.4∘C\text{ATR} = 27.8^\circ\text{C} - 26.4^\circ\text{C} ATR=1.4∘C\text{ATR} = 1.4^\circ\text{C}

    The correct option is ii).
    The annual Temperature Range (ATR) is ii) 1.4∘C\boxed{\text{ii) } \textbf{1.4}^\circ\textbf{C}}.

Part c

iii) 27.18∘C\text{iii) } \textbf{27.18}^\circ\textbf{C}

What is the Mean Annual Temperature (MAT)?

  1. Sum all the monthly temperature values.

    Sum of Temperatures=26.4+26.9+27.5+27.5+27.8+27.5+27.5+27.2+27.2+26.9+26.9+26.9\text{Sum of Temperatures} = 26.4 + 26.9 + 27.5 + 27.5 + 27.8 + 27.5 + 27.5 + 27.2 + 27.2 + 26.9 + 26.9 + 26.9 Sum of Temperatures=326.2∘C\text{Sum of Temperatures} = 326.2^\circ\text{C}

  2. Divide the sum by the number of months (12) to find the mean.

    MAT=Sum of TemperaturesNumber of Months\text{MAT} = \frac{\text{Sum of Temperatures}}{\text{Number of Months}} MAT=326.2∘C12\text{MAT} = \frac{326.2^\circ\text{C}}{12} MAT≈27.1833∘C\text{MAT} \approx 27.1833^\circ\text{C}

  3. Round the result to two decimal places.

    MAT≈27.18∘C\text{MAT} \approx 27.18^\circ\text{C}

    The correct option is iii).
    The Mean Annual Temperature (MAT) is iii) 27.18∘C\boxed{\text{iii) } \textbf{27.18}^\circ\textbf{C}}.

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