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Town X is on longitude 60^ exto extE and Town Y is on longitude 30^ exto extW. If the time in Town Y is 6 ext pm, what is the local time in Town X?

Geography

ScanSolve AI Answer

Answer

12 am (midnight)\text{12 am (midnight)}

Step-by-step solution

4 steps
  1. Identify the given information.

    Town X is on longitude 60∘E60^\circ \text{E}.
    Town Y is on longitude 30∘W30^\circ \text{W}.
    The time in Town Y is 6 pm6 \text{ pm}.

  2. Calculate the difference in longitude between Town X and Town Y.

    Since one town is East and the other is West, we add their longitudes.

    Longitude difference=60∘E+30∘W=90∘\text{Longitude difference} = 60^\circ \text{E} + 30^\circ \text{W} = 90^\circ
  3. Convert the longitude difference to time difference.

    We know that 15∘15^\circ of longitude corresponds to 1 hour of time difference.

    Time difference=Longitude difference15∘/hour=90∘15∘/hour=6 hours\text{Time difference} = \frac{\text{Longitude difference}}{15^\circ/\text{hour}} = \frac{90^\circ}{15^\circ/\text{hour}} = 6 \text{ hours}
  4. Determine the local time in Town X.

    Town X is East of Town Y. Locations to the East are ahead in time. Therefore, we add the time difference to the time in Town Y.

    Time in Town X=Time in Town Y+Time difference\text{Time in Town X} = \text{Time in Town Y} + \text{Time difference} Time in Town X=6 pm+6 hours\text{Time in Town X} = 6 \text{ pm} + 6 \text{ hours} Time in Town X=12 am (midnight)\text{Time in Town X} = 12 \text{ am (midnight)}

    The local time in Town X is 12 am (midnight)\text{12 am (midnight)}.

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