Recall the condition for independence of two events.

Two events $A$ and $B$ are independent if and only if $P(A \cap B) = P(A)P(B)$.

We are given:
$P(A) = 0.4$
$P(B) = 0.7$
$P(A \cap B) = 0.28$

We see that $P(A \cap B) = 0.28$ and $P(A)P(B) = 0.28$.
Since $P(A \cap B) = P(A)P(B)$, the events $A$ and $B$ are independent.

Option A states: "Yes, because $P(A \cap B) = P(A)P(B)$." This matches our finding.