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(0.25)^x−1 = 32

Mathematics

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Answer

−32-\frac{3}{2}

Step-by-step solution

6 steps
  1. Convert the decimal 0.25 to a fraction and express it as a power of 2.

    0.25=14=122=2−20.25 = \frac{1}{4} = \frac{1}{2^2} = 2^{-2}
  2. Express 32 as a power of 2.

    32=2532 = 2^5
  3. Substitute these into the given equation.

    (2−2)x−1=25(2^{-2})^{x-1} = 2^5
  4. Apply the exponent rule (am)n=amn(a^m)^n = a^{mn} to the left side of the equation.

    2−2(x−1)=252^{-2(x-1)} = 2^5 2−2x+2=252^{-2x+2} = 2^5
  5. Since the bases are equal, equate the exponents.

    −2x+2=5-2x+2 = 5
  6. Solve the linear equation for xx.

    −2x=5−2-2x = 5 - 2 −2x=3-2x = 3 x=−32x = -\frac{3}{2}

    The value of xx is −32\boxed{-\frac{3}{2}}.

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