1. a) iii) Name an application of a combination of a p-type and n-type semiconductor.
A common application is a diode.
1. b) Calculate the number of electrons that flow through a conductor if a current of 2 A flows for 4 s (charge on an electron = 1.6×10−19 C).
Step 1: Calculate the total charge Q that flows.
The relationship between current (I), charge (Q), and time (t) is given by Q=I×t.
Q=2A×4s
Q=8C
Step 2: Calculate the number of electrons (n).
The total charge Q is also equal to the number of electrons (n) multiplied by the charge of a single electron (e).
Q=n×e
n=eQ
n=1.6×10−19C8C
n=5×1019
The number of electrons that flow through the conductor is ∗5×1019∗.