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1(a) List prime numbers in K = \1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11\. Find the probability that a number selected from K is not prime. 1(b) Factorize completely (x+y)(2m-n) - m(x+y). 1(c) Calculate the

Mathematics

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  1. Solve 1(a)(i) - List prime numbers in KK.

    The set K={1,2,3,4,5,6,7,8,9,10,11}K = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11\}. Prime numbers are natural numbers greater than 1 that have no positive divisors other than 1 and themselves.
    The prime numbers in KK are 2,3,5,7,112, 3, 5, 7, 11.

    Prime numbers in K={2,3,5,7,11}\text{Prime numbers in } K = \{2, 3, 5, 7, 11\}
  2. Solve 1(a)(ii) - Find the probability that a number selected from KK is not prime.

    The total number of elements in KK is 11.
    The number of prime numbers in KK is 5.
    The number of non-prime numbers in KK is 11−5=611 - 5 = 6.

    P(not prime)=Number of non-prime numbersTotal number of elements=611P(\text{not prime}) = \frac{\text{Number of non-prime numbers}}{\text{Total number of elements}} = \frac{6}{11}

    The probability is 611\boxed{\frac{6}{11}}.

  3. Solve 1(b) - Factorize completely (x+y)(2m−n)−m(x+y)(x+y)(2m-n) - m(x+y).

    Factor out the common term (x+y)(x+y):

    (x+y)(2m−n)−m(x+y)=(x+y)[(2m−n)−m](x+y)(2m-n) - m(x+y) = (x+y)[(2m-n) - m]

    Simplify the expression inside the square brackets:

    (x+y)(2m−n−m)=(x+y)(m−n)(x+y)(2m-n-m) = (x+y)(m-n)

    The factorized expression is (x+y)(m−n)\boxed{(x+y)(m-n)}.

  4. Solve 1(c) - Calculate the total amount earned by the typist.

    Total sheets typed = 35.
    Cost for the first 8 sheets = GH¢ 68.00.
    Number of additional sheets = 35−8=2735 - 8 = 27 sheets.
    Cost per additional sheet = GH¢ 11.00.
    Cost for additional sheets = 27×GH¢ 11.00=GH¢ 297.0027 \times \text{GH¢ } 11.00 = \text{GH¢ } 297.00.
    Total amount earned = Cost for first 8 sheets + Cost for additional sheets

    Total amount=GH¢ 68.00+GH¢ 297.00=GH¢ 365.00\text{Total amount} = \text{GH¢ } 68.00 + \text{GH¢ } 297.00 = \text{GH¢ } 365.00

    The total amount earned is GH¢ 365.00\boxed{\text{GH¢ } 365.00}.

  5. Solve 2(a)(i) - Find the image of P(2,5)P(2, 5) translated by r=(−3,8)r = (-3, 8).

    To find the image P′(x′,y′)P'(x', y'), add the components of the translation vector to the coordinates of PP.

    P′(x′,y′)=(2+(−3),5+8)=(2−3,5+8)=(−1,13)P'(x', y') = (2 + (-3), 5 + 8) = (2 - 3, 5 + 8) = (-1, 13)

    The image of P(2,5)P(2, 5) is (−1,13)\boxed{(-1, 13)}.

  6. Solve 2(a)(ii) - Find the image Q′Q' of Q(−4,−6)Q(-4, -6) translated by r=(−3,8)r = (-3, 8).

    Similarly, add the components of the translation vector to the coordinates of QQ.

    Q′(x′,y′)=(−4+(−3),−6+8)=(−4−3,−6+8)=(−7,2)Q'(x', y') = (-4 + (-3), -6 + 8) = (-4 - 3, -6 + 8) = (-7, 2)

    The image of Q(−4,−6)Q(-4, -6) is (−7,2)\boxed{(-7, 2)}.

  7. Solve 2(b) - Calculate Joyce's and Richard's receipts.

    Total profit = GH¢ 9,000.00.
    Richard's manager's share = 13×GH¢ 9,000.00=GH¢ 3,000.00\frac{1}{3} \times \text{GH¢ } 9,000.00 = \text{GH¢ } 3,000.00.
    Remaining profit for distribution = GH¢ 9,000.00−GH¢ 3,000.00=GH¢ 6,000.009,000.00 - \text{GH¢ } 3,000.00 = \text{GH¢ } 6,000.00.
    Joyce's contribution = GH¢ 10,000.00.
    Richard's contribution = GH¢ 5,000.00.
    Ratio of contributions (Joyce : Richard) = 10,000:5,000=2:110,000 : 5,000 = 2 : 1.
    Total ratio parts = 2+1=32 + 1 = 3.

    • 2(b)(i) Joyce's receipt: Joyce's share from remaining profit = 23×GH¢ 6,000.00=GH¢ 4,000.00\frac{2}{3} \times \text{GH¢ } 6,000.00 = \text{GH¢ } 4,000.00. Joyce received GH¢ 4,000.00\boxed{\text{GH¢ } 4,000.00}.

    • 2(b)(ii) Richard's total receipt: Richard's share from remaining profit = 13×GH¢ 6,000.00=GH¢ 2,000.00\frac{1}{3} \times \text{GH¢ } 6,000.00 = \text{GH¢ } 2,000.00. Richard's total receipt = Richard's manager's share + Richard's share from remaining profit

      Richard’s total receipt=GH¢ 3,000.00+GH¢ 2,000.00=GH¢ 5,000.00\text{Richard's total receipt} = \text{GH¢ } 3,000.00 + \text{GH¢ } 2,000.00 = \text{GH¢ } 5,000.00

      Richard received in total GH¢ 5,000.00\boxed{\text{GH¢ } 5,000.00}.

  8. Solve 3(a) - Calculate Asana's total payment.

    Original daily wage = GH¢ 25.00.
    Increase in wage = 10%10\% of GH¢ 25.00=0.10×GH¢ 25.00=GH¢ 2.5025.00 = 0.10 \times \text{GH¢ } 25.00 = \text{GH¢ } 2.50.
    New daily wage = GH¢ 25.00+GH¢ 2.50=GH¢ 27.5025.00 + \text{GH¢ } 2.50 = \text{GH¢ } 27.50.
    Number of days worked = 30 days.
    Total payment = New daily wage ×\times Number of days worked

    Total payment=GH¢ 27.50×30=GH¢ 825.00\text{Total payment} = \text{GH¢ } 27.50 \times 30 = \text{GH¢ } 825.00

    Asana will be paid GH¢ 825.00\boxed{\text{GH¢ } 825.00}.

  9. Solve 3(b)(i) - Find the perimeter of the room.

    The dimensions of the L-shaped room are:
    Outer top length = 8 m
    Outer left length = 5 m
    Outer right length = 3 m
    Inner horizontal length = 8 m−5 m=38 \text{ m} - 5 \text{ m} = 3 m
    Inner vertical length = 5 m−3 m=25 \text{ m} - 3 \text{ m} = 2 m
    The perimeter is the sum of all outer side lengths:

    Perimeter=8 m+5 m+3 m+2 m+5 m+3 m=26 m\text{Perimeter} = 8 \text{ m} + 5 \text{ m} + 3 \text{ m} + 2 \text{ m} + 5 \text{ m} + 3 \text{ m} = 26 \text{ m}

    The perimeter is 26 m\boxed{26 \text{ m}}.

  10. Solve 3(b)(ii) - Find the area of the room.

    Divide the L-shaped room into two rectangles.
    Rectangle 1 (top part): 8 m×3 m8 \text{ m} \times 3 \text{ m}. Area1=8×3=24 m2_1 = 8 \times 3 = 24 \text{ m}^2.
    Rectangle 2 (bottom-left part): $5 \text{

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