List the prime numbers in K = 1, 2, 3, ..., 11. (b) Factorize completely: (x+y)(2m-n) - m(x+y).

The prime numbers in $K$ are $\boxed{\text{2, 3, 5, 7, 11}}$.

The set $K = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11\}$, so there are 11 elements.

From part (i), the prime numbers are $\{2, 3, 5, 7, 11\}$, which is 5 prime numbers.

Number of non-prime numbers = Total numbers - Number of prime numbers
$$
= 11 - 5 = 6
$$

$$
P(\text{not prime}) = \frac{\text{Number of non-prime numbers}}{\text{Total number of numbers}} = \frac{6}{11}
$$
The probability is $\boxed{\frac{6}{11}}$.

The common factor is $(x+y)$.

$$
(x+y)(2m-n) - m(x+y) = (x+y)[(2m-n) - m]
$$

$$
(x+y)(2m-n-m) = (x+y)(m-n)
$$
The completely factorized expression is $\boxed{(x+y)(m-n)}$.

Total sheets typed = 35 sheets.  
Sheets covered by the initial charge = 8 sheets.  
Additional sheets = $35 - 8 = 27$ sheets.

Cost per additional sheet = GH¢ 11.00.  
Cost for additional sheets = $27 \times \text{GH¢ } 11.00 = \text{GH¢ } 297.00$.

Cost for first 8 sheets = GH¢ 68.00.  
Total amount earned = Cost for first 8 sheets + Cost for additional sheets
$$
= \text{GH¢ } 68.00 + \text{GH¢ } 297.00 = \text{GH¢ } 365.00
$$
The amount earned is $\boxed{\text{GH¢ } 365.00}$.

$$
a = -3 - 2 = -5
$$
$$
b = 8 - 5 = 3
$$
The translation vector $r$ is $\boxed{\begin{pmatrix} -5 \\ 3 \end{pmatrix}}$.

$$
Q' = \begin{pmatrix} -4 + (-5) \\ -6 + 3 \end{pmatrix} = \begin{pmatrix} -9 \\ -3 \end{pmatrix}
$$
The image $Q'$ is $\boxed{(-9, -3)}$.

Total profit = GH¢ 9,000.00.  
Richard's manager's share = $\frac{1}{3} \times \text{GH¢ } 9,000.00 = \text{GH¢ } 3,000.00$.

Remaining profit = Total profit - Richard's manager's share
$$
= \text{GH¢ } 9,000.00 - \text{GH¢ } 3,000.00 = \text{GH¢ } 6,000.00
$$

Joyce's contribution : Richard's contribution = GH¢ 10,000.00 : GH¢ 5,000.00
$$
= 10,000 : 5,000 = 2 : 1
$$
The sum of the ratio parts is $2 + 1 = 3$.

Joyce's share = $\frac{2}{3} \times \text{GH¢ } 6,000.00 = \text{GH¢ } 4,000.00$.  
Joyce received $\boxed{\text{GH¢ } 4,000.00}$.

Richard's share = $\frac{1}{3} \times \text{GH¢ } 6,000.00 = \text{GH¢ } 2,000.00$.

Richard's total = Richard's manager's share + Richard's share from remaining profit
$$
= \text{GH¢ } 3,000.00 + \text{GH¢ } 2,000.00 = \text{GH¢ } 5,000.00
$$
Richard received in total $\boxed{\text{GH¢ } 5,000.00}$.

Original daily wage = GH¢ 25.00.  
Increase = 10% of GH¢ 25.00 = $0.10 \times \text{GH¢ } 25.00 = \text{GH¢ } 2.50$.

New daily wage = Original daily wage + Increase = GH¢ 25.00 + GH¢ 2.50 = GH¢ 27.50.

Total payment = New daily wage $\times$ Number of days worked