(ii) Find the set of real values of x for which |(x+3)/(x-5)| = (x+3)/(x-5).

April 5, 2026Mathematics

ScanSolve AI Answer

April 5, 2026

Answer

we need to solve the inequality $\frac{x+3}{x-5} \ge 0$

Here are the solutions to the questions:

1. (ii) Find the set of real values of $x$ for which $\left|\frac{x+3}{x-5}\right| = \frac{x+3}{x-5}$ . The condition $|A| = A$ implies that $A \ge 0$ . Therefore, we need to solve the inequality $\frac{x+3}{x-5} \ge 0$ .

Step 1: Identify critical points where the numerator or denominator is zero. $x+3 = 0 \implies x = -3$ $x-5 = 0 \implies x = 5$ (Note: $x \ne 5$ because the denominator cannot be zero).

Step

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1. (ii) Find the set of real values of x for which |(x+3)/(x-5)| = (x+3)/(x-5).

Asked on April 5, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 5, 2026

Here are the solutions to the questions: 1. (ii) Find the set of real values of x for which |(x+3)/(x-5)| = (x+3)/(x-5). The condition |A| = A implies that A 0. Therefore, we need to solve the inequality (x+3)/(x-5) 0. Step 1: Identify critical points where the numerator or denominator is zero. x+3 = 0 x = -3 x-5 = 0 x = 5 (Note: x 5 because the denominator cannot be zero). Step