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Discuss how gender inequality in a relationship could contribute to Sexual Abuse, Teenage pregnancy, and STIs. What are the effects of being in a submissive relationship? Define power, masculinity, and femininity. Propose THREE strategies that could help eliminate gender inequality.

Mathematics

ScanSolve AI Answer

  1. The least-squares regression equation is
y^=b0+b1x1+b2x2+b3x3\hat{y} = b_0 + b_1 x_1 + b_2 x_2 + b_3 x_3

where b0=3.47b_0 = 3.47, b1=−0.0042b_1 = -0.0042, b2=0.012b_2 = 0.012, b3=0.10b_3 = 0.10.

Substitute the values:

y^=3.47+(−0.0042)x1+0.012x2+0.10x3\hat{y} = 3.47 + (-0.0042) x_1 + 0.012 x_2 + 0.10 x_3 y^=3.47−0.0042x1+0.012x2+0.10x3\hat{y} = 3.47 - 0.0042 x_1 + 0.012 x_2 + 0.10 x_3

\hat{y} = 3.47 - 0.0042 x_1 + 0.012 x_2 + 0.10 x_3

  1. The p-value for x1x_1 is 0.002.

Since 0.002<0.050.002 < 0.05, the relationship between the response and x1x_1 is significant.

The t-value is −3.07-3.07, and ∣t∣=3.07>2|t| = 3.07 > 2 also indicates significance.

Yes, since P = 0.002 < 0.05

  1. The slope for x1x_1 is b1=−0.0042<0b_1 = -0.0042 < 0.

Thus, when x1x_1 increases by 1 unit (with x2x_2 and x3x_3 held constant), the mean response decreases by 0.0042 units.

decreases by 0.0042 units per 1-unit increase in x_1

  1. Substitute x1=50x_1 = 50, x2=3x_2 = 3, x3=0.5x_3 = 0.5 into the equation:
y^=3.47−0.0042(50)+0.012(3)+0.10(0.5)\hat{y} = 3.47 - 0.0042(50) + 0.012(3) + 0.10(0.5)

Compute x1x_1 term:

−0.0042×50=−0.21-0.0042 \times 50 = -0.21

Compute x2x_2 term:

0.012×3=0.0360.012 \times 3 = 0.036

Compute x3x_3 term:

0.10×0.5=0.050.10 \times 0.5 = 0.05

Now add step-by-step:

3.47−0.21=3.263.47 - 0.21 = 3.26 3.26+0.036=3.2963.26 + 0.036 = 3.296 3.296+0.05=3.3463.296 + 0.05 = 3.346

Round to three decimal places (consistent with coefficient precision):

y^=3.346\hat{y} = 3.346

3.35

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