Discuss how gender inequality in a relationship could contribute to Sexual Abuse, Teenage pregnancy, and STIs. What are the effects of being in a submissive relationship? Define power, masculinity, and femininity. Propose THREE strategies that could help eliminate gender inequality.

Mathematics
Discuss how gender inequality in a relationship could contribute to Sexual Abuse, Teenage pregnancy, and STIs. What are the effects of being in a submissive relationship? Define power, masculinity, and femininity. Propose THREE strategies that could help eliminate gender inequality.

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Answer

y^=3.470.0042x1+0.012x2+0.10x3\hat{y} = 3.47 - 0.0042 x_1 + 0.012 x_2 + 0.10 x_3

  1. The least-squares regression equation is

y^=b0+b1x1+b2x2+b3x3\hat{y} = b_0 + b_1 x_1 + b_2 x_2 + b_3 x_3

where b0=3.47b_0 = 3.47, b1=0.0042b_1 = -0.0042, b2=0.012b_2 = 0.012, b3=0.10b_3 = 0.10.

Substitute the values:

y^=3.47+(0.0042)x1+0.012x2+0.10x3\hat{y} = 3.47 + (-0.0042) x_1 + 0.012 x_2 + 0.10 x_3

y^=3.470.0042x1+0.012x2+0.10x3\hat{y} = 3.47 - 0.0042 x_1 + 0.012 x_2 + 0.10 x_3

\hat{y = 3.47 - 0.0042 x_1 + 0.012 x_2 + 0.10 x_3}

  1. The p-value for x1x_1 is 0.0020.002.

Since 0.002<0.050.002 < 0.05, the relationship between the response and x1x_1 is significant.

The t-value is 3.07-3.07, and t=3.07>2|t| = 3.07 > 2 also indicates significance.

Yes, since P = 0.002 < 0.05

  1. The slope for x1x_1 is b1=0.0042<0b_1 = -0.0042 < 0.

Thus, when x1x_1 increases by 11 unit (with x2x_2 and x3x_3 held constant), the mean response decreases by 0.00420.0042 units.

decreases by 0.0042 units per 1-unit increase in x_1

  1. Substitute x1=50x_1 = 50, x2=3x_2 = 3, x3=0.5x_3 = 0.5 into the equation:

y^=3.470.0042(50)+0.012(3)+0.10(0.5)\hat{y} = 3.47 - 0.0042(50) + 0.012(3) + 0.10(0.5)

Compute x1x_1 term:

0.0042×50=0.21-0.0042 \times 50 = -0.21

Compute x2x_2 term:

0.012×3=0.0360.012 \times 3 = 0.036

Compute x3x_3 term:

0.10×0.5=0.050.10 \times 0.5 = 0.05

Now add step-by-step:

3.470.21=3.263.47 - 0.21 = 3.26

3.26+0.036=3.2963.26 + 0.036 = 3.296

3.296+0.05=3.3463.296 + 0.05 = 3.346

Round to three decimal places (consistent with coefficient precision):

y^=3.346\hat{y} = 3.346

3.35

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Quick Answer
  1. The least-squares regression equation is y = b_0 + b_1 x_1 + b_2 x_2 + b_3 x_3 where b_0 = 3.47, b_1 = -0.0042, b_2 = 0.012, b_3 = 0.10.
  2. The p-value for x_1 is 0.002.
  3. Since 0.002 < 0.05, the relationship between the response and x_1 is significant.
  4. The t-value is -3.07, and |t| = 3.07 > 2 also indicates significance.
Discuss how gender inequality in a relationship could contribute to Sexual Abuse, Teenage pregnancy, and STIs. What are the effects of being in a submissive relationship? Define power, masculinity, and femininity. Propose THREE strategies that could help eliminate gender inequality.
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
1. The least-squares regression equation is y = b_0 + b_1 x_1 + b_2 x_2 + b_3 x_3 where b_0 = 3.47, b_1 = -0.0042, b_2 = 0.012, b_3 = 0.10. Substitute the values: y = 3.47 + (-0.0042) x_1 + 0.012 x_2 + 0.10 x_3 y = 3.47 - 0.0042 x_1 + 0.012 x_2 + 0.10 x_3 y = 3.47 - 0.0042 x_1 + 0.012 x_2 + 0.10 x_3 2. The p-value for x_1 is 0.002. Since 0.002 < 0.05, the relationship between the response and x_1 is significant. The t-value is -3.07, and |t| = 3.07 > 2 also indicates significance. Yes, since P = 0.002 < 0.05 3. The slope for x_1 is b_1 = -0.0042 < 0. Thus, when x_1 increases by 1 unit (with x_2 and x_3 held constant), the mean response decreases by 0.0042 units. decreases by 0.0042 units per 1-unit increase in x_1 4. Substitute x_1 = 50, x_2 = 3, x_3 = 0.5 into the equation: y = 3.47 - 0.0042(50) + 0.012(3) + 0.10(0.5) Compute x_1 term: -0.0042 × 50 = -0.21 Compute x_2 term: 0.012 × 3 = 0.036 Compute x_3 term: 0.10 × 0.5 = 0.05 Now add step-by-step: 3.47 - 0.21 = 3.26 3.26 + 0.036 = 3.296 3.296 + 0.05 = 3.346 Round to three decimal places (consistent with coefficient precision): y = 3.346 3.35