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(1 + theta)( theta - 1) - 2 2 theta

Mathematics

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سأقوم بحل المسائل واحدة تلو الأخرى.

السؤال (11):
(1+sin⁡θ)(sin⁡θ−1)−2sin⁡2θ(1 + \sin \theta)(\sin \theta - 1) - 2 \sin^2 \theta

الخطوة 1: تبسيط الجزء الأول من التعبير.
نستخدم المتطابقة (a+b)(b−a)=b2−a2(a+b)(b-a) = b^2 - a^2. هنا a=1a=1 و b=sin⁡θb=\sin \theta.

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