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वीर पूर्व कविताको आधारमा प्रहहरूले दिइएको योगदानको समीक्षा गर्नुहोस्।

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Answer

72cm7\sqrt{2} cm

Step-by-step solution

4 steps

घुंघरू को अर्धगोलाकार मानते हैं।

  1. घुंघरू का व्यास 14 cm है।

    इसकी त्रिज्या r=142=7r = \dfrac{14}{2} = 7 cm।

  2. घुंघरू (अर्धगोल) के वक्र सतह क्षेत्रफल की सूत्र

    2πr22\pi r^{2}

    =2π(7)2=2π×49=98π= 2\pi (7)^{2} = 2\pi \times 49 = 98\pi cm2^{2}।

  3. गोले का पृष्ठीय क्षेत्रफल

    4πR2=98π4\pi R^{2} = 98\pi 4R2=984R^{2} = 98 R2=984=492R^{2} = \dfrac{98}{4} = \dfrac{49}{2}

    R=492=72=722R = \sqrt{\dfrac{49}{2}} = \dfrac{7}{\sqrt{2}} = \dfrac{7\sqrt{2}}{2} cm।

  4. गोले का व्यास =2R=2×722=72= 2R = 2 \times \dfrac{7\sqrt{2}}{2} = 7\sqrt{2} cm।

    7\sqrt{2} cm

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