Construct truth table method whether or contradictory it contingency, tautology Pa(~P0~9)

Mathematics

ScanSolve AI Answer

Answer

contingency\text{contingency}

Step-by-step solution

4 steps

To determine whether the expression P∧(∼P∨Q)P \land (\sim P \lor Q) is a tautology, contradiction, or contingency, we construct a truth table.

  1. Identify atomic propositions and their negations

    The atomic propositions are PP and QQ. We also need ∼P\sim P.

  2. Evaluate the disjunction ∼P∨Q\sim P \lor Q

    This column will show the truth values for the expression (∼P∨Q)(\sim P \lor Q).

  3. Evaluate the main conjunction P∧(∼P∨Q)P \land (\sim P \lor Q)

    This column will show the truth values for the entire expression P∧(∼P∨Q)P \land (\sim P \lor Q).

    Truth Table:

    PPQQ∼P\sim P∼P∨Q\sim P \lor QP∧(∼P∨Q)P \land (\sim P \lor Q)
    TTFTT
    TFFFF
    FTTTF
    FFTTF
  4. Analyze the final column

    The final column for P∧(∼P∨Q)P \land (\sim P \lor Q) contains both 'T' (True) and 'F' (False) values.

    • A tautology is an expression that is always true.
    • A contradiction is an expression that is always false.
    • A contingency is an expression that is neither a tautology nor a contradiction (i.e., its truth value depends on the truth values of its components).

    Since the final column has a mix of 'T' and 'F' values, the expression is a contingency.

    The expression P∧(∼P∨Q)P \land (\sim P \lor Q) is a contingency.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question