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2 R+ - R+ + R - = 3 2500 + R1600 = 4 R15x60 = 8 1/6 of 60 = = 1/6 x 60/1 =

Mathematics

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4 parts
1.3

R4100\text{R4100}

1.4

R900\text{R900}

1.8
10

Step-by-step solution

9 steps

Here are the solutions to the problems:

Part 1.2

The problem "R+ - R+R-" is incomplete and cannot be solved as written. Please provide the full problem.

Part 1.3

R4100\text{R4100}

  1. Identify the numbers to be added.

    2500+R16002500 + R1600
  2. Perform the addition.

    2500+1600=41002500 + 1600 = 4100

    The sum is R4100\boxed{\text{R4100}}.

Part 1.4

R900\text{R900}

  1. Identify the numbers for multiplication.

    R15×60R15 \times 60
  2. Perform the multiplication.

    15×60=90015 \times 60 = 900

    The product is R900\boxed{\text{R900}}.

Part 1.810

  1. Convert "16\frac{1}{6} of 60" into a multiplication problem, as shown in your work.

    16×601\frac{1}{6} \times \frac{60}{1}
  2. Multiply the numerators and the denominators.

    1×606×1=606\frac{1 \times 60}{6 \times 1} = \frac{60}{6}
  3. Simplify the fraction.

    606=10\frac{60}{6} = 10

    The result is 10\boxed{10}.

Part 1.66

  1. Identify the numbers for division.

    60÷1060 \div 10
  2. Perform the division.

    60÷10=660 \div 10 = 6

    The result is 6\boxed{6}.

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