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(2(x-2)) + 1/(6(x-2)) - 1/(3(x-1)) (x+1) + 2/((x-1)2) - x2/((x-1)3)

Mathematics

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Answer

x3(x−2)(x−1)\frac{x}{3(x-2)(x-1)}

−2x2+3x−3(x+1)(x−1)3\frac{-2x^2 + 3x - 3}{(x+1)(x-1)^3}

Step-by-step solution

9 steps

Here are the solutions for the given expressions.

:

12(x−2)+16(x−2)−13(x−1)\frac{1}{2(x-2)} + \frac{1}{6(x-2)} - \frac{1}{3(x-1)}
  1. Find the least common denominator (LCD).

    The denominators are 2(x−2)2(x-2), 6(x−2)6(x-2), and 3(x−1)3(x-1). The LCD is 6(x−2)(x−1)6(x-2)(x-1).

  2. Rewrite each fraction with the LCD.

    1⋅3(x−1)2(x−2)⋅3(x−1)+1⋅(x−1)6(x−2)⋅(x−1)−1⋅2(x−2)3(x−1)⋅2(x−2)\frac{1 \cdot 3(x-1)}{2(x-2) \cdot 3(x-1)} + \frac{1 \cdot (x-1)}{6(x-2) \cdot (x-1)} - \frac{1 \cdot 2(x-2)}{3(x-1) \cdot 2(x-2)} =3(x−1)6(x−2)(x−1)+x−16(x−2)(x−1)−2(x−2)6(x−2)(x−1)= \frac{3(x-1)}{6(x-2)(x-1)} + \frac{x-1}{6(x-2)(x-1)} - \frac{2(x-2)}{6(x-2)(x-1)}
  3. Combine the numerators over the common denominator.

    =3(x−1)+(x−1)−2(x−2)6(x−2)(x−1)= \frac{3(x-1) + (x-1) - 2(x-2)}{6(x-2)(x-1)}
  4. Simplify the numerator.

    =3x−3+x−1−2x+46(x−2)(x−1)= \frac{3x - 3 + x - 1 - 2x + 4}{6(x-2)(x-1)} =(3x+x−2x)+(−3−1+4)6(x−2)(x−1)= \frac{(3x + x - 2x) + (-3 - 1 + 4)}{6(x-2)(x-1)} =2x+06(x−2)(x−1)= \frac{2x + 0}{6(x-2)(x-1)} =2x6(x−2)(x−1)= \frac{2x}{6(x-2)(x-1)}
  5. Reduce the fraction.

    =x3(x−2)(x−1)= \frac{x}{3(x-2)(x-1)}

    The simplified expression is:

    x3(x−2)(x−1)\boxed{\frac{x}{3(x-2)(x-1)}}

    :

    1x+1+2(x−1)2−x2(x−1)3\frac{1}{x+1} + \frac{2}{(x-1)^2} - \frac{x^2}{(x-1)^3}
  6. Find the least common denominator (LCD).

    The denominators are (x+1)(x+1), (x−1)2(x-1)^2, and (x−1)3(x-1)^3. The LCD is (x+1)(x−1)3(x+1)(x-1)^3.

  7. Rewrite each fraction with the LCD.

    1⋅(x−1)3(x+1)(x−1)3+2⋅(x+1)(x−1)(x−1)2⋅(x+1)(x−1)−x2⋅(x+1)(x−1)3⋅(x+1)\frac{1 \cdot (x-1)^3}{(x+1)(x-1)^3} + \frac{2 \cdot (x+1)(x-1)}{(x-1)^2 \cdot (x+1)(x-1)} - \frac{x^2 \cdot (x+1)}{(x-1)^3 \cdot (x+1)} =(x−1)3(x+1)(x−1)3+2(x2−1)(x+1)(x−1)3−x2(x+1)(x+1)(x−1)3= \frac{(x-1)^3}{(x+1)(x-1)^3} + \frac{2(x^2-1)}{(x+1)(x-1)^3} - \frac{x^2(x+1)}{(x+1)(x-1)^3}
  8. Combine the numerators over the common denominator.

    =(x−1)3+2(x2−1)−x2(x+1)(x+1)(x−1)3= \frac{(x-1)^3 + 2(x^2-1) - x^2(x+1)}{(x+1)(x-1)^3}
  9. Expand and simplify the numerator.

    Recall (x−1)3=x3−3x2+3x−1(x-1)^3 = x^3 - 3x^2 + 3x - 1.

    =(x3−3x2+3x−1)+(2x2−2)−(x3+x2)(x+1)(x−1)3= \frac{(x^3 - 3x^2 + 3x - 1) + (2x^2 - 2) - (x^3 + x^2)}{(x+1)(x-1)^3} =x3−3x2+3x−1+2x2−2−x3−x2(x+1)(x−1)3= \frac{x^3 - 3x^2 + 3x - 1 + 2x^2 - 2 - x^3 - x^2}{(x+1)(x-1)^3}

    Combine like terms:

    =(x3−x3)+(−3x2+2x2−x2)+(3x)+(−1−2)(x+1)(x−1)3= \frac{(x^3 - x^3) + (-3x^2 + 2x^2 - x^2) + (3x) + (-1 - 2)}{(x+1)(x-1)^3} =0−2x2+3x−3(x+1)(x−1)3= \frac{0 - 2x^2 + 3x - 3}{(x+1)(x-1)^3} =−2x2+3x−3(x+1)(x−1)3= \frac{-2x^2 + 3x - 3}{(x+1)(x-1)^3}

    The simplified expression is:

    −2x2+3x−3(x+1)(x−1)3\boxed{\frac{-2x^2 + 3x - 3}{(x+1)(x-1)^3}}
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