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Solve 3 81 = x and evaluate ( 500 - 5)/( 10) using logarithm laws.

Mathematics

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2 parts
b

x=4x=4

c
2

Step-by-step solution

9 steps

Part b· 4 steps

Solve

  1. Convert the logarithmic equation to an exponential equation.

    The definition of a logarithm states that log⁡ba=x\log_b a = x is equivalent to bx=ab^x = a.
    Applying this to log⁡381=x\log_3 81 = x:

    3x=813^x = 81
  2. Express 81 as a power of 3.

    81=3×3×3×3=3481 = 3 \times 3 \times 3 \times 3 = 3^4
  3. Substitute 343^4 for 81 in the equation.

    3x=343^x = 3^4
  4. Equate the exponents since the bases are the same.

    x=4x = 4

    The solution is x=4\boxed{x=4}.

Part c2

Evaluate using logarithm laws

log⁡500−log⁡5log⁡10\frac{\log 500 - \log 5}{\log 10}
  1. Apply the logarithm law for subtraction in the numerator

    log⁡M−log⁡N=log⁡(MN)\log M - \log N = \log \left(\frac{M}{N}\right).

    log⁡500−log⁡5=log⁡(5005)\log 500 - \log 5 = \log \left(\frac{500}{5}\right)
  2. Simplify the argument of the logarithm in the numerator.

    log⁡(5005)=log⁡100\log \left(\frac{500}{5}\right) = \log 100
  3. Evaluate the numerator.

    Since the base of log⁡\log is 10 (common logarithm), log⁡100\log 100 asks "10 to what power equals 100?".

    log⁡100=log⁡10102=2\log 100 = \log_{10} 10^2 = 2
  4. Evaluate the denominator.

    log⁡10=log⁡10101=1\log 10 = \log_{10} 10^1 = 1
  5. Substitute the evaluated numerator and denominator back into the expression.

    21=2\frac{2}{1} = 2

    The evaluated expression is 2\boxed{2}.

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