[5/2, 8:56 PM] ..🙂‍↔️ Mercy UABS: Two wires, one of copper and one of steel, each of length 1.5 m and diameter 2.0 mm, are joined end-to-end to form a composite wire of length 3.0 m. A load of 200 N is applied to the end of the composite wire. [5/2, 8:57 PM] ..🙂‍↔️ Mercy UABS: Calculate: The total extension of the composite wire. The stress in each wire.

Here's how to calculate the stress and total extension of the composite wire: To solve this, we need the Young's Modulus for copper and steel. We will use the following standard values: Young's Modulus for Copper (E_c) = 1.1 × 10^11 Pa Young's Modulus for Steel (E_s) = 2.0 × 10^11 Pa Given: Length of copper wire (L_c) = 1.5 m Length of steel wire (L_s) = 1.5 m Diameter (d) = 2.0 mm = 2.0 × 10^-3 m Load (F) = 200 N 1. Calculate the stress in each wire. Step 1: Calculate the cross-sectional area of the wire. The diameter of the wire is d = 2.0 mm = 2.0 × 10^-3 m. The radius is r = d/2 = 1.0 × 10^-3 m. The