[5/2, 8:56 PM] ..🙂‍↔️ Mercy UABS: Two wires, one of copper and one of steel, each of length 1.5 m and diameter 2.0 mm, are joined end-to-end to form a composite wire of length 3.0 m. A load of 200 N is applied to the end of the composite wire. [5/2, 8:57 PM] ..🙂‍↔️ Mercy UABS: Calculate: The total extension of the composite wire. The stress in each wire.

Here's how to calculate the stress and total extension of the composite wire:

To solve this, we need the Young's Modulus for copper and steel. We will use the following standard values:

• Young's Modulus for Copper ($E_c$) = $1.1 \times 10^{11} \text{ Pa}$
• Young's Modulus for Steel ($E_s$) = $2.0 \times 10^{11} \text{ Pa}$

Given:

• Length of copper wire ($L_c$) = 1.5 m
• Length of steel wire ($L_s$) = 1.5 m
• Diameter ($d$) = 2.0 mm = $2.0 \times 10^{-3}$ m
• Load ($F$) = 200 N

1. Calculate the stress in each wire.

Step 1: Calculate the cross-sectional area of the wire.
The diameter of the wire is $d = 2.0 \text{ mm} = 2.0 \times 10^{-3} \text{ m}$.
The radius is $r = d/2 = 1.0 \times 10^{-3} \text{ m}$.
The