= 2³ x 5² = 8 x 25 = 200 minutes

50. = 2^3 \times 5^2 = 8 \times 25 = 200 minutes$$

Step 3: Convert 200 minutes to hours and minutes.

$$200 minutes = 3 hours and 20 minutes$$

Step 4: Identify the common departure times within the 8:00 AM to 5:00 PM window.
The vehicles both depart at 8:00 AM.
The next common departure will be 3 hours and 20 minutes after 8:00 AM:

$$8:00 AM + 3 hours 20 minutes = 11:20 AM$$

The next common departure will be 3 hours and 20 minutes after 11:20 AM:

$$11:20 AM + 3 hours 20 minutes = 2:40 PM$$

The next common departure would be 3 hours and 20 minutes after 2:40 PM:

$$2:40 PM + 3 hours 20 minutes = 6:00 PM$$

This time (6:00 PM) is outside the specified range of 8:00 AM to 5:00 PM.

The times of the day when the two vehicles will leave the park at the same time are:

• 8:00 AM
• 11:20 AM
• 2:40 PM

Part 3: How can traffic jam be controlled?

Traffic jams can be controlled through various strategies:

• Improved Public Transportation: Investing in efficient and accessible public transport reduces the number of private vehicles on the road.
• Traffic Management Systems: Implementing smart traffic lights, real-time traffic monitoring, and dynamic lane management can optimize traffic flow.
• Road Infrastructure Development: Expanding roads, building bypasses, and improving intersections can increase capacity and reduce bottlenecks.
• Encouraging Carpooling and Cycling: Promoting shared rides and non-motorized transport options can decrease individual vehicle usage.
• Congestion Pricing: Charging drivers for using roads during peak hours can deter non-essential travel and reduce congestion.