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7us logarithm tables to evaluate sqrt(0.0452x2.63/1.56)

Mathematics

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0.4893

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Haya, tutasuluhisha swali hili tena kwa undani zaidi.

Swali la 7: Tumia jedwali la logariti kutathmini 0.0142×2.631.56\sqrt{\frac{0.0142 \times 2.63}{1.56}}.

Wacha X=0.0142×2.631.56X = \sqrt{\frac{0.0142 \times 2.63}{1.56}}.
Ili kutatua hili kwa kutumia logariti, tunachukua logariti ya pande zote mbili:

log⁡X=log⁡((0.0142×2.631.56)12)\log X = \log \left( \left(\frac{0.0142 \times 2.63}{1.56}\right)^{\frac{1}{2}} \right)

Tunatumia sheria za logariti: log⁡(ab)=blog⁡a\log(a^b) = b \log a, log⁡(ab)=log⁡a+log⁡b\log(ab) = \log a + \log b, na log⁡(ab)=log⁡a−log⁡b\log\left(\frac{a}{b}\right) = \log a - \log b.

log⁡X=12(log⁡(0.0142)+log⁡(2.63)−log⁡(1.56))\log X = \frac{1}{2} \left( \log(0.0142) + \log(2.63) - \log(1.56) \right)
  1. Tafuta logariti za kila namba kutoka jedwali la logariti.

    • log⁡(0.0142)\log(0.0142): Namba hii ina sifuri mbili kabla ya namba muhimu ya kwanza, hivyo tabia (characteristic) yake ni 2ˉ\bar{2}. Mantisa ya 142 ni 0.1523. Hivyo, log⁡(0.0142)=2ˉ.1523\log(0.0142) = \bar{2}.1523.
    • log⁡(2.63)\log(2.63): Namba hii ina tarakimu moja kabla ya desimali, hivyo tabia yake ni 0. Mantisa ya 263 ni 0.4200. Hivyo, log⁡(2.63)=0.4200\log(2.63) = 0.4200.
    • log⁡(1.56)\log(1.56): Namba hii ina tarakimu moja kabla ya desimali, hivyo tabia yake ni 0. Mantisa ya 156 ni 0.1931. Hivyo, log⁡(1.56)=0.1931\log(1.56) = 0.1931.
  2. Badilisha thamani hizi kwenye fomula ya log⁡X\log X na ufanye hesabu za kujumlisha na kutoa.

    log⁡X=12(2ˉ.1523+0.4200−0.1931)\log X = \frac{1}{2} (\bar{2}.1523 + 0.4200 - 0.1931)

    Kwanza, jumlisha logariti za namba kwenye nambari:

    2ˉ.1523+0.4200=(−2+0.1523)+0.4200=−2+(0.1523+0.4200)=−2+0.5723=1ˉ.5723\bar{2}.1523 + 0.4200 = (-2 + 0.1523) + 0.4200 = -2 + (0.1523 + 0.4200) = -2 + 0.5723 = \bar{1}.5723

    Sasa, toa logariti ya namba kwenye kigawanyo:

    1ˉ.5723−0.1931=(−1+0.5723)−0.1931=−1+(0.5723−0.1931)=−1+0.3792=1ˉ.3792\bar{1}.5723 - 0.1931 = (-1 + 0.5723) - 0.1931 = -1 + (0.5723 - 0.1931) = -1 + 0.3792 = \bar{1}.3792

    Hivyo, log⁡(0.0142×2.631.56)=1ˉ.3792\log\left(\frac{0.0142 \times 2.63}{1.56}\right) = \bar{1}.3792.

  3. Gawanya matokeo kwa 2.

    log⁡X=12(1ˉ.3792)\log X = \frac{1}{2} (\bar{1}.3792)

    Ili kugawanya 1ˉ.3792\bar{1}.3792 kwa 2, tunabadilisha tabia 1ˉ\bar{1} ili iwe namba hasi inayoweza kugawanywa na 2 bila salio, huku tukihakikisha mantisa inabaki chanya.
    1ˉ.3792=−1+0.3792\bar{1}.3792 = -1 + 0.3792. Tunaweza kuandika −1-1 kama −2+1-2 + 1.
    Hivyo, 1ˉ.3792=−2+1+0.3792=−2+1.3792\bar{1}.3792 = -2 + 1 + 0.3792 = -2 + 1.3792.
    Sasa gawanya kwa 2:

    log⁡X=12(−2+1.3792)=−22+1.37922=−1+0.6896=1ˉ.6896\log X = \frac{1}{2} (-2 + 1.3792) = \frac{-2}{2} + \frac{1.3792}{2} = -1 + 0.6896 = \bar{1}.6896
  4. Tafuta antilog ya 1ˉ.6896\bar{1}.6896.

    Mantisa 0.6896 inalingana na takriban 4.893 kutoka jedwali la antilogariti.
    Tabia 1ˉ\bar{1} inamaanisha kuzidisha kwa 10−110^{-1}.

    X=4.893×10−1X = 4.893 \times 10^{-1} X=0.4893X = 0.4893

    Jibu: 0.4893

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