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8 women till 2 hectares in 5 days. How many hectares can 15 men till in 12 days if men and women work at the same rate? What is the perimeter of a room 6m by 4m?

Mathematics

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Answers

4 parts
a

20 m20 \text{ m}

b

12 m212 \text{ m}^2

c

24 m224 \text{ m}^2

d

12 m212 \text{ m}^2

Step-by-step solution

8 steps

5)

Step 1: Determine the work rate per person per day.
The work done is tilling farm land, measured in hectares.
Given: 8 women till 2 hectares in 5 days.
Work rate per person per day = HectaresNumber of people×Number of days\frac{\text{Hectares}}{\text{Number of people} \times \text{Number of days}}

Rate=2 hectares8 women×5 days=240hectaresperson⋅day=120hectaresperson⋅day\text{Rate} = \frac{2 \text{ hectares}}{8 \text{ women} \times 5 \text{ days}} = \frac{2}{40} \frac{\text{hectares}}{\text{person} \cdot \text{day}} = \frac{1}{20} \frac{\text{hectares}}{\text{person} \cdot \text{day}}

Step 2: Calculate the total hectares tilled by 15 men in 12 days using the same rate.
Assuming men and women work at the same rate.

Hectares=Rate×Number of people×Number of days\text{Hectares} = \text{Rate} \times \text{Number of people} \times \text{Number of days} Hectares=120hectaresperson⋅day×15 men×12 days\text{Hectares} = \frac{1}{20} \frac{\text{hectares}}{\text{person} \cdot \text{day}} \times 15 \text{ men} \times 12 \text{ days} Hectares=15×1220 hectares\text{Hectares} = \frac{15 \times 12}{20} \text{ hectares} Hectares=18020 hectares\text{Hectares} = \frac{180}{20} \text{ hectares} Hectares=9 hectares\text{Hectares} = 9 \text{ hectares}

15 men will till 9 hectares\boxed{9 \text{ hectares}} of farm land.

6)
The room is a rectangle with length 6 m6 \text{ m} and width 4 m4 \text{ m}.
The carpet is a rectangle with length 4 m4 \text{ m} and width 3 m3 \text{ m}.

Part a· 2 steps

Find the perimeter of the room

  1. Identify the dimensions of the room.

    Length (LL) = 6 m6 \text{ m}
    Width (WW) = 4 m4 \text{ m}

  2. Use the formula for the perimeter of a rectangle, P=2(L+W)P = 2(L + W).

    P=2(6 m+4 m)P = 2(6 \text{ m} + 4 \text{ m}) P=2(10 m)P = 2(10 \text{ m}) P=20 mP = 20 \text{ m}

    The perimeter of the room is 20 m\boxed{20 \text{ m}}.

Part b

12 m212 \text{ m}^2

Find the area of the carpet

  1. Identify the dimensions of the carpet.

    Length (LcL_c) = 4 m4 \text{ m}
    Width (WcW_c) = 3 m3 \text{ m}

  2. Use the formula for the area of a rectangle, A=L×WA = L \times W.

    Ac=4 m×3 mA_c = 4 \text{ m} \times 3 \text{ m} Ac=12 m2A_c = 12 \text{ m}^2

    The area of the carpet is 12 m2\boxed{12 \text{ m}^2}.

Part c

24 m224 \text{ m}^2

Find the Area of the room

  1. Identify the dimensions of the room.

    Length (LL) = 6 m6 \text{ m}
    Width (WW) = 4 m4 \text{ m}

  2. Use the formula for the area of a rectangle, A=L×WA = L \times W.

    Ar=6 m×4 mA_r = 6 \text{ m} \times 4 \text{ m} Ar=24 m2A_r = 24 \text{ m}^2

    The area of the room is 24 m2\boxed{24 \text{ m}^2}.

Part d

12 m212 \text{ m}^2

Find the area of the uncovered portion

  1. The area of the uncovered portion is the area of the room minus the area of the carpet.

    Auncovered=Ar−AcA_{\text{uncovered}} = A_r - A_c
  2. Substitute the calculated areas.

    Auncovered=24 m2−12 m2A_{\text{uncovered}} = 24 \text{ m}^2 - 12 \text{ m}^2 Auncovered=12 m2A_{\text{uncovered}} = 12 \text{ m}^2

    The area of the uncovered portion is 12 m2\boxed{12 \text{ m}^2}.

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