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9x2 - 12x + 4 x3 - 8

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2 parts
a

(3x−2)2(3x-2)^2

b

(x−2)(x2+2x+4)(x-2)(x^2+2x+4)

Step-by-step solution

5 steps

Sawa, Mbari. Haya hapa maswali mawili ya mwisho ya kuweka katika vigawo.

Part a· 3 steps

Weka 9x2−12x+49x^2 - 12x + 4 katika vigawo.

  1. Tambua kuwa huu ni mraba kamili wa trinomial.

    Usemi huu una fomu a2x2−2abx+b2a^2x^2 - 2abx + b^2.
    Hapa, a2x2=9x2  ⟹  ax=3xa^2x^2 = 9x^2 \implies ax = 3x.
    Na b2=4  ⟹  b=2b^2 = 4 \implies b = 2.

  2. Thibitisha neno la kati.

    Neno la kati linapaswa kuwa −2abx=−2(3x)(2)=−12x-2abx = -2(3x)(2) = -12x. Hii inalingana na usemi wetu.

  3. Andika usemi katika vigawo.

    9x2−12x+4=(3x−2)29x^2 - 12x + 4 = (3x - 2)^2

    Jibu: (3x−2)2\boxed{(3x-2)^2}

Part b

(x−2)(x2+2x+4)(x-2)(x^2+2x+4)

Weka x3−8x^3 - 8 katika vigawo.

  1. Tambua kuwa huu ni tofauti ya ujazo (difference of cubes).

    Fomula ya tofauti ya ujazo ni a3−b3=(a−b)(a2+ab+b2)a^3 - b^3 = (a-b)(a^2 + ab + b^2).
    Hapa, a3=x3  ⟹  a=xa^3 = x^3 \implies a = x.
    Na b3=8  ⟹  b=2b^3 = 8 \implies b = 2.

  2. Tumia fomula ya tofauti ya ujazo.

    x3−8=(x−2)(x2+x⋅2+22)x^3 - 8 = (x - 2)(x^2 + x \cdot 2 + 2^2) x3−8=(x−2)(x2+2x+4)x^3 - 8 = (x - 2)(x^2 + 2x + 4)

    Jibu: (x−2)(x2+2x+4)\boxed{(x-2)(x^2+2x+4)}

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