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यदि A = [5 2 1, 4 1 1, 9 3 2] हो, तो |A| ज्ञात कीजिये। x के मान ज्ञात कीजिये यदि

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यहाँ दिए गए प्रश्न का हल इस प्रकार है:

यदि A=[112213549]A = \begin{bmatrix} 1 & 1 & 2 \\ 2 & 1 & 3 \\ 5 & 4 & 9 \end{bmatrix}, तो ∣A∣|A| ज्ञात कीजिए।

  1. सारणिक $|A|$ का मान पहली पंक्ति के अनुदिश सह-खंड विस्तार (cofactor expansion) का उपयोग करके ज्ञात कीजिए।

    ∣A∣=1⋅∣1349∣−1⋅∣2359∣+2⋅∣2154∣|A| = 1 \cdot \begin{vmatrix} 1 & 3 \\ 4 & 9 \end{vmatrix} - 1 \cdot \begin{vmatrix} 2 & 3 \\ 5 & 9 \end{vmatrix} + 2 \cdot \begin{vmatrix} 2 & 1 \\ 5 & 4 \end{vmatrix}
  2. 2×22 \times 2 सारणिकों का मान ज्ञात कीजिए।

    ∣1349∣=(1)(9)−(3)(4)=9−12=−3\begin{vmatrix} 1 & 3 \\ 4 & 9 \end{vmatrix} = (1)(9) - (3)(4) = 9 - 12 = -3 ∣2359∣=(2)(9)−(3)(5)=18−15=3\begin{vmatrix} 2 & 3 \\ 5 & 9 \end{vmatrix} = (2)(9) - (3)(5) = 18 - 15 = 3 ∣2154∣=(2)(4)−(1)(5)=8−5=3\begin{vmatrix} 2 & 1 \\ 5 & 4 \end{vmatrix} = (2)(4) - (1)(5) = 8 - 5 = 3
  3. इन मानों को $|A|$ के विस्तार में प्रतिस्थापित कीजिए।

    ∣A∣=1(−3)−1(3)+2(3)|A| = 1(-3) - 1(3) + 2(3) ∣A∣=−3−3+6|A| = -3 - 3 + 6 ∣A∣=0|A| = 0

    ∣A∣|A| का मान है: 0\boxed{0}

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