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A) A cone has a radius of 3m and a height of 4m. Calculate its surface area and volume. b) A sphere has a radius of 3m. Finds its Surface area and volume.

Mathematics

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  1. a) A cone has a radius of 3m and a height of 4m. Calculate its surface area and volume.

    • Step 1: Kokotoa urefu wa slant (ll) kwa kutumia Theorem ya Pythagoras. l=r2+h2l = \sqrt{r^2 + h^2} l=(3 m)2+(4 m)2l = \sqrt{(3 \text{ m})^2 + (4 \text{ m})^2} l=9 m2+16 m2l = \sqrt{9 \text{ m}^2 + 16 \text{ m}^2} l=25 m2l = \sqrt{25 \text{ m}^2} l=5 ml = 5 \text{ m}
    • Step 2: Kokotoa eneo la uso (AA) la koni. Fomula ni jumla ya eneo la duara la chini na eneo la uso wa kando. A=πr2+πrlA = \pi r^2 + \pi r l A=π(3 m)2+π(3 m)(5 m)A = \pi (3 \text{ m})^2 + \pi (3 \text{ m})(5 \text{ m}) A=9π m2+15π m2A = 9\pi \text{ m}^2 + 15\pi \text{ m}^2 A=24π m2A = 24\pi \text{ m}^2
    • Step 3: Kokotoa ujazo (VV) wa koni. V=13πr2hV = \frac{1}{3}\pi r^2 h V=13π(3 m)2(4 m)V = \frac{1}{3}\pi (3 \text{ m})^2 (4 \text{ m}) V=13π(9 m2)(4 m)V = \frac{1}{3}\pi (9 \text{ m}^2) (4 \text{ m}) V=12π m3V = 12\pi \text{ m}^3
    • Jibu la Mwisho: Eneo la uso=24π m2,Ujazo=12π m3\boxed{\mathbf{\text{Eneo la uso} = 24\pi \text{ m}^2, \text{Ujazo} = 12\pi \text{ m}^3}}

b) A sphere has a radius of 3m. Finds its Surface area and volume.

*   **Step 1:** Kokotoa eneo la uso ($A$) la tufe.
    $$
    A = 4\pi r^2
    $$
    $$
    A = 4\pi (3 \text{ m})^2
    $$
    $$
    A = 4\pi (9 \text{ m}^2)
    $$
    $$
    A = 36\pi \text{ m}^2
    $$
*   **Step 2:** Kokotoa ujazo ($V$) wa tufe.
    $$
    V = \frac{4}{3}\pi r^3
    $$
    $$
    V = \frac{4}{3}\pi (3 \text{ m})^3
    $$
    $$
    V = \frac{4}{3}\pi (27 \text{ m}^3)
    $$
    $$
    V = 4\pi (9 \text{ m}^3)
    $$
    $$
    V = 36\pi \text{ m}^3
    $$
*   **Jibu la Mwisho:**
    $$
    \boxed{\mathbf{\text{Eneo la uso} = 36\pi \text{ m}^2, \text{Ujazo} = 36\pi \text{ m}^3}}
    $$
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