A baker uses (3)/(4) kg of flour, (5)/(6) kg of sugar, and (1)/(3) kg of cocoa. He sells the mixture for GHC 120 per kg. Find the total mass of the mixture and the total sales.

b) Step 1: Add the masses of flour, sugar, and cocoa. Mass of flour = (3)/(4) kg Mass of sugar = (5)/(6) kg Mass of cocoa = (1)/(3) kg Total mixture = (3)/(4) + (5)/(6) + (1)/(3) kg Step 2: Find the least common multiple (LCM) of the denominators 4, 6, and 3. The LCM of 4, 6, and 3 is 12. Step 3: Convert each fraction to an equivalent fraction with a denominator of 12 and add them. (3)/(4) = (3 × 3)/(4 × 3) = (9)/(12) (5)/(6) = (5 × 2)/(6 × 2) = (10)/(12) (1)/(3) = (1 × 4)/(3 × 4) = (4)/(12) Total mixture = (9)/(12) + (10)/(12) + (4)/(12) = (9 + 10 + 4)/(12) = (23)/(12) kg Step 4: The fraction (23)/(12) is already in its simplest form because 23 is a prime number and 12 is not a multiple of 23. The total mixture is (23)/(12) kg. c) Step 1: Use the total mass from part (b), which is (23)/(12) kg. Selling price per kg = GHC 120 Step 2: Calculate the total sales by multiplying the total mass by the selling price per kg. Total sales = Total mixture × Price per kg Total sales = (23)/(12) kg × 120 GHC/kg Total sales = 23 × (120)/(12) GHC Total sales = 23 × 10 GHC Total sales = 230 GHC The total sales are GHC 230. 2. a) Step 1: Express 0.000684 in standard form. To move the decimal point after the first non-zero digit (6), we move it 4 places to the right. 0.000684 = 6.84 × 10^-4 Step 2: Round 6.84 × 10^-4 to 3 significant figures. The number 6.84 already has 3 significant figures. So, 0.000684 in standard form and rounded to 3 significant figures is 6.84 × 10^-4. b) Step 1: Solve the equation 2^x × 8 = 64. Divide both sides by 8. 2^x = (64)/(8) 2^x = 8 Step 2: Express 8 as a power of 2. 8 = 2^3 Step 3: Substitute this back into the equation. 2^x = 2^3 Step 4: Since the bases are the same, equate the exponents. x = 3 The solution is x=3. Send me the next one 📸