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Four loaves of bread and three packets of milk cost a total of Ksh. 410. Three similar loaves of bread and two similar packets of milk cost a total of Ksh. 290. Find the cost of one loaf of bread and the cost of one packet of milk.

Mathematics

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Answer

Gharama ya mkate: Sh. 50, Gharama ya maziwa: Sh. 70\text{Gharama ya mkate: Sh. 50, Gharama ya maziwa: Sh. 70}

Step-by-step solution

4 steps
  1. Fafanua vigezo na uandike milinganyo.

    Acha bb iwe gharama ya mkate mmoja na mm iwe gharama ya pakiti moja ya maziwa.
    Kutokana na taarifa ya kwanza, tuna mlinganyo:

    4b+3m=410(Mlinganyo 1)4b + 3m = 410 \quad \text{(Mlinganyo 1)}

    Kutokana na taarifa ya pili, tuna mlinganyo:

    3b+2m=290(Mlinganyo 2)3b + 2m = 290 \quad \text{(Mlinganyo 2)}
  2. Tumia njia ya kuondoa (elimination method) kutatua milinganyo.

    Ili kuondoa mm, zidisha Mlinganyo 1 kwa 2 na Mlinganyo 2 kwa 3:
    Zidisha Mlinganyo 1 kwa 2:

    2(4b+3m)=2(410)⇒8b+6m=820(Mlinganyo 3)2(4b + 3m) = 2(410) \Rightarrow 8b + 6m = 820 \quad \text{(Mlinganyo 3)}

    Zidisha Mlinganyo 2 kwa 3:

    3(3b+2m)=3(290)⇒9b+6m=870(Mlinganyo 4)3(3b + 2m) = 3(290) \Rightarrow 9b + 6m = 870 \quad \text{(Mlinganyo 4)}
  3. Toa Mlinganyo 3 kutoka Mlinganyo 4 ili kupata thamani ya bb.

    (9b+6m)−(8b+6m)=870−820(9b + 6m) - (8b + 6m) = 870 - 820 9b−8b+6m−6m=509b - 8b + 6m - 6m = 50 b=50b = 50

    Hivyo, gharama ya mkate mmoja ni Sh. 50.

  4. Badilisha thamani ya bb katika Mlinganyo 1 ili kupata thamani ya mm.

    4b+3m=4104b + 3m = 410 4(50)+3m=4104(50) + 3m = 410 200+3m=410200 + 3m = 410 3m=410−2003m = 410 - 200 3m=2103m = 210 m=2103m = \frac{210}{3} m=70m = 70

    Hivyo, gharama ya pakiti moja ya maziwa ni Sh. 70.

    Gharama ya mkate: Sh. 50, Gharama ya maziwa: Sh. 70\text{Gharama ya mkate: Sh. 50, Gharama ya maziwa: Sh. 70}
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