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Which is a better deal: 6x340ml cans for R36 or 3x2L bottles for R45?

Mathematics

ScanSolve AI Answer

Step-by-step solution

3 steps

To determine the best value, we need to calculate the cost per liter for each special offer.

  1. Calculate the cost per liter for the 340ml340 \text{ml} cans.

    A pack contains 6×340ml6 \times 340 \text{ml} cans for R36.
    Total volume in one pack of cans:

    6×340 ml=2040 ml6 \times 340 \text{ ml} = 2040 \text{ ml}

    Convert milliliters to liters:

    2040 ml=20401000 L=2.04 L2040 \text{ ml} = \frac{2040}{1000} \text{ L} = 2.04 \text{ L}

    Cost per liter for cans:

    R362.04 L≈R17.65 per liter\frac{\text{R}36}{2.04 \text{ L}} \approx \text{R}17.65 \text{ per liter}
  2. Calculate the cost per liter for the 2 liter2 \text{ liter} bottles.

    A pack contains 3×2 liter3 \times 2 \text{ liter} bottles for R45.00.
    Total volume in one pack of bottles:

    3×2 L=6 L3 \times 2 \text{ L} = 6 \text{ L}

    Cost per liter for bottles:

    R45.006 L=R7.50 per liter\frac{\text{R}45.00}{6 \text{ L}} = \text{R}7.50 \text{ per liter}
  3. Compare the cost per liter for both specials.

    Cost per liter for cans: R17.65
    Cost per liter for bottles: R7.50

    Since R7.50 is less than R17.65, the 2 liter2 \text{ liter} bottles offer a better value per liter.

    The best option to pay is the 3 x 2 liters @ R45.00 per pack of 3.

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