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A cellular network offers two plans. Plan 1 costs R2.50 per minute. Plan 2 costs R10 plus R3 per minute. Which plan is cheaper for 20 minutes? Explain how changes in fixed fees and per-minute costs af

Mathematics

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Step-by-step solution

3 steps
  1. Determine which company is cheaper for 20 minutes.

    From previous questions:
    Company 1's cost formula: C1=2.50mC_1 = 2.50m
    Company 2's cost formula: C2=10+3mC_2 = 10 + 3m

    Calculate the cost for 20 minutes for Company 1:

    C1=2.50×20C_1 = 2.50 \times 20 C1=50.00C_1 = 50.00

    The cost for Company 1 for 20 minutes is R50.00.

    Calculate the cost for 20 minutes for Company 2:

    C2=10+(3×20)C_2 = 10 + (3 \times 20) C2=10+60C_2 = 10 + 60 C2=70.00C_2 = 70.00

    The cost for Company 2 for 20 minutes is R70.00.

    Compare the costs:
    R50.00 (Company 1) is less than R70.00 (Company 2).
    Therefore, Company 1 is cheaper for 20 minutes.

  2. Answer Question 7.1.

    A real-life example of a similar linear relationship is the cost of hiring a taxi, which often involves a fixed base fare plus a cost per kilometer traveled.

  3. Answer Question 7.2.

    Consider the general linear equation y=mx+cy = mx + c, where cc is the fixed fee (y-intercept) and mm is the cost per minute (gradient).

    • If the fixed fee increases: The graph will shift upwards parallel to its original position. The y-intercept will move higher on the y-axis.

    • If the cost per minute increases: The graph will become steeper. The gradient of the line will increase, causing it to rotate upwards around the y-intercept.

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