A clock shows fifteen minutes to twelve. The hour and minute hands are between 11 and 12, closer to 12. The minute hand is at 9. Is the clock correct?

John's share corresponds to 2 parts of the ratio.

$$2 \text{ parts} = \text{Sh } 12000$$ $$1 \text{ part} = \frac{\text{Sh } 12000}{2} = \text{Sh } 6000$$

Paul's share corresponds to 3 parts of the ratio.

$$\text{Paul's share} = 3 \times \text{Sh } 6000 = \text{Sh } 18000$$

$$\text{Difference} = \text{Paul's share} - \text{John's share}$$ $$\text{Difference} = \text{Sh } 18000 - \text{Sh } 12000$$ $$\text{Difference} = \text{Sh } 6000$$

Paul got $\boxed{\text{Sh } 6000}$ more money than John.

: Electric Poles
Electric poles are fixed 4.5 m apart in a straight line. We need to find how many electric poles are needed to cover a distance of 22 m.

The number of intervals is the total distance divided by the distance between poles.

$$\text{Number of intervals} = \frac{\text{Total distance}}{\text{Distance between poles}}$$ $$\text{Number of intervals} = \frac{22 \text{ m}}{4.5 \text{ m}}$$ $$\text{Number of intervals} = \frac{22}{4.5} = \frac{220}{45} = \frac{44}{9} \approx 4.888...$$

Since we need to cover the entire distance of 22 m, we must have enough intervals. If we have $N$ poles, there are $N-1$ intervals between them. The total length covered by these intervals must be at least 22 m.

$$(N-1) \times 4.5 \text{ m} \ge 22 \text{ m}$$ $$N-1 \ge \frac{22}{4.5}$$ $$N-1 \ge 4.888...$$

Since the number of intervals ($N-1$) must be a whole number, we round up to the next integer to ensure the distance is fully covered.

$$N-1 = 5$$ $$N = 5 + 1$$ $$N = 6$$

This means 6 poles are needed. The first pole is at 0 m, and the 6th pole will be at $5 \times 4.5 \text{ m} = 22.5 \text{ m}$, which covers the required 22 m distance.

The number of electric poles needed is $\boxed{6}$.