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A diagram shows two similar right-angled triangles, riangle ABE and riangle ACD. BE is parallel to CD. AE = 6 m, ED = y m, BE = 5 m, CD = 8 m. AB = x m. Find x and y.

Mathematics

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Geometry Problem (from diagram):

  1. Identify similar triangles.

    The diagram shows two similar right-angled triangles: △ABE\triangle ABE and △ACD\triangle ACD. This is because BE is parallel to CD (both are perpendicular to AD).

  2. Use the ratio of corresponding sides to find yy.

    From similar triangles, we have:

    AEAD=BECD\frac{AE}{AD} = \frac{BE}{CD}

    Given AE=6 mAE = 6 \, \text{m}, ED=y mED = y \, \text{m}, so AD=AE+ED=(6+y) mAD = AE + ED = (6+y) \, \text{m}.
    Given BE=5 mBE = 5 \, \text{m} and CD=8 mCD = 8 \, \text{m}.
    Substitute these values into the ratio:

    66+y=58\frac{6}{6+y} = \frac{5}{8} 6×8=5×(6+y)6 \times 8 = 5 \times (6+y) 48=30+5y48 = 30 + 5y 48−30=5y48 - 30 = 5y 18=5y18 = 5y y=185y = \frac{18}{5} y=3.6 my = 3.6 \, \text{m}
  3. Use the Pythagorean theorem to find xx.

    In the right-angled triangle △ABE\triangle ABE, ABAB is the hypotenuse (xx), AEAE is 6 m6 \, \text{m}, and BEBE is 5 m5 \, \text{m}.

    x2=AE2+BE2x^2 = AE^2 + BE^2 x2=62+52x^2 = 6^2 + 5^2 x2=36+25x^2 = 36 + 25 x2=61x^2 = 61 x=61 mx = \sqrt{61} \, \text{m}

    The values are:

    x=61 m\boxed{x = \sqrt{61} \, \text{m}} y=3.6 m\boxed{y = 3.6 \, \text{m}}

    1. a) Compound Interest:

  4. Identify the given values.

    Principal amount P=4000 FP = 4000 \, \text{F}
    Annual interest rate r=6%=0.06r = 6\% = 0.06
    Compounded quarterly, so n=4n = 4 times per year
    Time t=5t = 5 years

  5. Use the compound interest formula A=P(1+rn)ntA = P\left(1 + \frac{r}{n}\right)^{nt}.

    A=4000(1+0.064)4×5A = 4000 \left(1 + \frac{0.06}{4}\right)^{4 \times 5} A=4000(1+0.015)20A = 4000 \left(1 + 0.015\right)^{20} A=4000(1.015)20A = 4000 \left(1.015\right)^{20} A≈4000×1.346855007A \approx 4000 \times 1.346855007 A≈5387.420028A \approx 5387.420028
  6. Round to two decimal places for currency.

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